Response:
y_red / y_blue = 1.11
Clarification:
To determine the image for each wavelength, we'll utilize the lens maker's equation
1 /f = 1 /o + 1 /i
Where f signifies the focal length, o represents the object distance, and i indicates the image distance
For red light
1 / i = 1 / f - 1 / o
1 / i_red = 1 / f_red - 1 / o
1 / i_red = 1 / 19.57 - 1/30
1 / i_red = 1.776 10-2
i_red = 56.29 cm
For blue light
1 / i_blue = 1 / f_blue - 1 / o
1 / i_blue = 1 / 18.87 - 1/30
1 / i_blue = 1.966 10-2
i_blue = 50.863 cm
Next, we will compute the magnification ratio
m = y ’/ h = - i / o
y ’= - h i / o
For red light
y_red ’= - 5 56.29 / 30
y_red ’= - 9.3816 cm
For blue light
y_blue ’= 5 50.863 / 30
y_blue ’= - 8.47716 cm
The ratio of the heights of both images is
y_red ’/ y_blue’ = 9.3816 / 8.47716
y_red / y_blue = 1.107
y_red / y_blue = 1.11
Answer:
The number of photons emitted each second is
Explanation:
Let 'n' stand for the quantity of photons released by the bulb.
Provided Information:
The bulb radiates energy at a rate of 100 J per second (E).
Wavelength of emitted light is (λ) = 525 nm = 
The energy of a photon is calculated by:
Where,

Now, if we have 'n' photons, the total energy is equivalent to the energy of a single photon multiplied by the count of photons. Thus,

To express in terms of 'n', we find:

Insert the provided values and solve for 'n'. The resulting calculation yields

Consequently,
photons are discharged every second.