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spayn
1 month ago
12

Lucy took 3 hours to cover 2/3 of a journey. She covered the remaining 60 miles in 2 hours. What was the average speed for the w

hole journey?
Physics
1 answer:
serg [3.5K]1 month ago
5 0

The accurate answer is 36 miles per hour

Explanation:

To calculate the average speed, start by determining the total distance and total time Lucy traveled, as average speed is the total distance divided by the total time.

Total Distance

Lucy is known to have covered 2/3 of the total distance initially, later finishing the journey with 60 miles. Therefore, the last segment of 60 miles corresponds to 1/3 of the total distance.

\frac{2}{3} + \frac{1}{3} = \frac{3}{3} (Total distance)

Consequently, since 60 miles equals one-third, multiplying this by 3 gives the total distance: 180 miles.

This indicates the total distance traversed is 180 miles

Total Time

Lucy took 3 hours for the first part of her journey and 2 hours for the second, leading to a total time of 5 hours (3 + 2 = 5)

Determining Average Speed

Average speed =\frac{Distance}{time}

Average speed = \frac{180 m}{5 h}

Average speed = 36m/h

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A 0.050-kg lump of clay moving horizontally at 12 m/s strikes and sticks to a stationary 0.15-kg cart that can move on a frictio
Ostrovityanka [3204]

Answer:

Explanation:

According to the parameters provided,

mass of the clay lump, m₁ = 0.05 kg

initial velocity of the lump, u₁ = 12 m/s

mass of the cart, m₂ = 0.15 kg

initial speed of the cart, u₂ = 0

As the clay adheres to the cart, we have an inelastic collision scenario. Let v represent the combined speed of both the cart and lump post-collision. Given that momentum is conserved, we have:

m_1u_1+m_2u_2=(m_1+m_2)v

v=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}

v=\dfrac{0.05\ kg\times 12\ m/s+0}{0.05\ kg+0.15\ kg}

The resultant speed is v = 3 m/s.

Thus, the final speed of both cart and lump following the collision is 3 m/s. This concludes the solution.

3 0
1 month ago
(a) Calculate the absolute pressure at the bottom of a fresh- water lake at a depth of 27.5 m. Assume the density of the water i
kicyunya [3294]

Response:

a) P = 370.993\,kPa, b) F = 25.948\,kN

Clarification:

a) The absolute pressure at a depth of 27.5 meters is:

P = P_{atm} + P_{man}

P = 101.3\,kPa + \left(1000\,\frac{kg}{m^{3}}\right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (27.5\,m)\cdot \left(\frac{1\,kPa}{1000\,Pa} \right)

P = 370.993\,kPa

b) The force applied by the water is:

F = (P - P_{atm})\cdot A

F = (370.993\,kPa-101.3\,kPa)\cdot \left(\frac{\pi}{4} \right)\cdot (0.35\,m)^{2}

F = 25.948\,kN

5 0
1 month ago
Read 2 more answers
A loop of wire with cross-sectional area 1 m2 is inserted into a uniform magnetic field with initial strength 1 T. The field is
serg [3582]

Answer:

La magnitud del EMF es 0.00055  volts

Explanation:

El EMF inducido es proporcional al cambio en el flujo magnético según la ley de Faraday:

emf\,=-\,N\, \frac{d\Phi}{dt}

Como en nuestro caso hay solo un lazo de alambre, entonces N=1 y obtenemos:

emf\,=-\,N\, \frac{d\Phi}{dt}

Necesitamos expresar el flujo magnético dada la geometría del problema;

\Phi=B\,\,Adonde A es el área de la bobina que permanece constante con el tiempo, y B es el campo magnético que cambia con el tiempo. Por lo tanto, la ecuación para el EMF se convierte en:

emf\,=-\,N\, \frac{d\Phi}{dt} = \frac{d\Phi}{dt} =-\frac{d\,(B\,A)}{dt} =-\,A\,\frac{d\,(B)}{dt}=- 1\,m^2(2\,\,T/h})= -2\,\,m^2\,T/(3600\,\,s)= -0.00055\,Volts

8 0
16 days ago
. A 40.0-kg child standing on a frozen pond throws a 0.500-kg stone to the east with a speed of 5.00 m/s. Neglecting friction be
Softa [3030]
A 40 kg child throws a 0.5 kg stone at a velocity of 5 m/s. To find the recoil, we apply the conservation of momentum formula: m1•v1 + m2•v2 = 0, where m1 is the mass of the child, and v1 is the child's recoil velocity. Applying the known values results in 40•v1 = -0.5 × 5, leading to v1 = -2.5 / 40, which simplifies to v1 = -0.0625 m/s. Thus, the child's recoil speed is 0.0625 m/s.
6 0
25 days ago
Which statements describe velocity and acceleration? Check all that apply. Velocity equals displacement divided by time. All vel
kicyunya [3294]

Response:

Velocity is defined as displacement divided by time.

Acceleration is defined as the change in velocity divided by time.

To determine average velocity, one can utilize multiple velocities and their combined time.

7 0
1 month ago
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