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ivanzaharov
10 days ago
12

A 100-watt light bulb radiates energy at a rate of 100 J/s. (The watt, a unit of power or energy over time, is defined as 1 J/s.

) If all of the light emitted has a wavelength of 525nm, how many photons are emitted per second?
Physics
1 answer:
Keith_Richards [2.2K]10 days ago
8 0

Answer:

2.64\times 10^{20} The number of photons emitted each second is

Explanation:

Let 'n' stand for the quantity of photons released by the bulb.

Provided Information:

The bulb radiates energy at a rate of 100 J per second (E).

Wavelength of emitted light is (λ) = 525 nm = 525\times 10^{-9}\ m

The energy of a photon is calculated by:

Where,

E_0=\frac{hc}{\lambda}

Now, if we have 'n' photons, the total energy is equivalent to the energy of a single photon multiplied by the count of photons. Thus,

h\to Planck's\ constant=6.626\times 10^{-34}\ Js\\\\c\to Speed\ of \ light=3\times 10^{8}\ m/s

To express in terms of 'n', we find:

E=nE_0\\\\E=\frac{nhc}{\lambda}

Insert the provided values and solve for 'n'. The resulting calculation yields

n=\frac{E\lambda}{hc}

Consequently,

photons are discharged every second.n=\frac{100\times 525\times 10^{-9}}{6.626\times 10^{-34}\times 3\times 10^{8}}\\\\n=2.64\times 10^{20}

2.64\times 10^{20}

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