In the absence of a specific question posed, below are the potential inquiries along with their respective answers:
P(fewer than 4 tosses)
= P(one toss) + P(two tosses) + P(three tosses)
= (3/4) + (3/4)(1/4) + (3/4)(1/4)^2
= 0.984375
Expected value
= 1 / p
= 1 / (3/4)
= 4 / 3
Variance
= (1 - p) / p^2
= (1 - (3/4)) / (3/4)^2
= (1/4) / (9/16)
= 4 / 9
Standard deviation
= sqrt(Variance)
= sqrt(4 / 9)
= 2 / 3
96 soldiers will remain unassigned and the arrangement will consist of 52 rows.
The diagrams for parts A and C are included here. For part B, we have circle O. We begin by drawing two radii OA and OC, connecting points A and C to create chord AC. The radius intersects chord AC at point B, bisecting AC into equal segments AB and BC. This gives us two triangles, ΔOBA and ΔOBC, where OA equals OC (since they're radii), OB equals OB (by the reflexive property), and AB is equal to BC (as stated in the question). By applying the SSS triangle congruence criterion, we conclude that ΔOBA is congruent to ΔOBC, allowing us to deduce that ∡OBA equals ∡OBC, both measuring 90°. Thus, OB is perpendicular to AC. Moving on to part D, we again work with circle O and draw the two radii OA and OC, joining points A and C to create chord AC. The radius intersects AC at point B, where AB is perpendicular to AC, meaning ∡B equals 90°. We then consider the right triangles ΔOBA and ΔOBC, and given OA equals OC (the radii), and OB equals OB (reflexive property), we conclude through the HL triangle congruence that ΔOBA is congruent to ΔOBC. Consequently, we find BA equal to BC, thus OB bisects AC.
Answer:
the expression is -64937.4.5.53.94x
Step-by-step explanation:
Solution:
Let x be the distance in miles from the house to the theater.
Total time taken for the trip 
Then average speed 
Terrence walks at a speed of 2 miles per hour to the theater and returns home at 40 miles per hour.
Thus, Average Speed 
mi/hr
Both average speeds must be equivalent. Hence, we can express this as:
Consequently, the distance from home is 13.125 miles.
