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IrinaK
20 days ago
7

Q2 - Square Everything (0.25 points) Write a function called square_all that takes an input called collection that you assume to

be a list or tuple of numbers. This function should return a new list, which contains the square of each value in collection. To do so, inside the function, you will define a new list, use a loop to loop through the input list, use an operator to square the current value, and use the append method to add this to your output list. After the loop, return the output list.g
Computers and Technology
1 answer:
zubka84 [942]20 days ago
4 0
Refer to the explanation Define the function square_all() that receives a list of integers. This function should return a new list containing the square values of all integers found within the provided list. def square_all(num_list): #Initiate an empty list to store results. sq_list = [] #Iterate through the length of the list. for index in range(0, len(num_list)): #Calculate the square of the current value and add it to the result list sq_list. sq_list.append(num_list[index] * num_list[index]) #Return the squared values of all integers in num_list. return sq_list #Declare and initialize a list of integers. intList = [2, 4] #Invoke the square_all() function and pass the above list as an argument. Show the returned list. print(square_all(intList))
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Sushant is a new manager and he wants to share his ideas and working protocol with his team.Compare the advantages and disadvant
oksian1 [797]

Answer:

Benefits of Oral Communication

  1. Utilizing visual aids such as PowerPoint during discussions can enhance his team's understanding of his concepts and procedures.
  2. Staff responses tend to be more immediate and sincere compared to written replies.

Drawbacks of Oral Communication

  1. If Sushant struggles with stage fright or lacks strong communication skills, it may negatively impact the team's perception of him.
  2. There is a risk that staff may forget portions of Sushant's spoken communication, as written information is generally more reliable for retention.

Benefits of Written Communication

  1. A well-crafted memo articulates Sushant's ideas and procedures clearly to the staff.
  2. A feedback questionnaire could be included for staff input.
  3. Clearly stated goals and objectives.

Drawbacks of Written Communication

  1. Excessively lengthy written material may pose challenges for comprehension or retention.

It is advisable for Sushant to prioritize written communication to share his ideas and protocols effectively.

3 0
1 month ago
Which kind of file would be hurt most by lossy compression algorithm
oksian1 [797]

Response: a file containing audio

Clarification:

8 0
10 days ago
Read 2 more answers
Determine the number of bytes necessary to store an uncompressed binary image of size 4000 × 3000 pixels
maria [879]

Response: 1,500,000 bytes.

Clarification:

If we assume the image dimensions are 4000 pixels in width and 3000 pixels in height, the total uncompressed image will consist of 4000*3000= 12,000,000 pixels.

In the case of a binary image, each pixel can have only two values, which necessitates one bit for each pixel.

This indicates that we need to accommodate 12,000,000 bits.

Given that 1 byte equals 8 bits.

So, to store an uncompressed binary image sized 4000 x 3000 pixels, 12,000,000/8 bytes is required ⇒ 1,500,000 bytes.

3 0
26 days ago
Mia is disappointed with how her latest video games are playing on her computer; the images are slow
amid [800]

Answer:

She is expressing dissatisfaction with her images loading slowly and lagging; she should consider acquiring a new GPU since, well, it's quite evident that GPU stands for graphics processing unit, which makes the connection clear.

8 0
10 days ago
python Consider this data sequence: "3 11 5 5 5 2 4 6 6 7 3 -8". Any value that is the same as the immediately preceding value i
oksian1 [797]

int currentNumber,previousNumber = -1, countDuplicates = 0;

do {

cin >> currentNumber;

if ( previousNumber == -1) {

previousNumber = currentNumber;

}else {

if ( previousNumber == currentNumber )

countDuplicates++;

else

previousNumber = currentNumber;

}

} while(currentNumber > 0 );

cout << countDuplicates;

7 0
1 month ago
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