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dem82
11 days ago
8

An administrator has been working within an organization for over 10 years. He has moved between different IT divisions within t

he company and has retained privileges from each of the jobs that he's had during his tenure. Recently, supervisors admonished him for making unauthorized changes to systems. He once again made an unauthorized change that resulted in an unexpected outage and management decided to terminate his employment at the company. He came back to work the following day to clean out his desk and belongings, and during this time he installed a malicious script that was scheduled to run as a logic bomb on the first day of the following month. The script will change administrator passwords, delete files, and shut down over 100 servers in the datacenter. What could have discovered problems with this user's account while he was employed
Computers and Technology
1 answer:
amid [800]11 days ago
5 0
User permissions and access control. Explanation: The question describes a situation where a former employee returned to the office and installed malicious software on a computer that was set to execute a logic bomb on the first day of the next month. This script is designed to alter administrator passwords, erase files, and shut down over 100 servers within the data center. Issues related to that account might include unauthorized access by users who have permissions to system resources. If such individuals gain unauthorized access, they could easily alter or damage the system's operations. Additionally, the firewall may need to be disabled to recognize the harmful script, highlighting the necessity of keeping firewalls operational to prevent attacks from unauthorized users. Furthermore, if user roles are not clearly defined, it increases the risk of unauthorized modifications to the system, potentially leading to unforeseen outages.
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Assume that the following variables have been properly declared and initialized.
ivann1987 [930]

Answer:

boolean rsvp;

int selection;

String option1;

String option2;

(a) if(rsvp){

System.out.println("Attending");

} else {

System.out.println("Not attending");

}

(b) if (selection == 1){

System.out.println("Beef");

} else if (selection == 2){

System.out.println("Chicken");

} else if (selection == 3) {

System.out.println("Pasta");

} else {

System.out.println("Fish");

}

(c) switch(selection){

case 1:

if(rsvp){

option1 = "Thanks for attending. You will be served beef.";

} else{

option1 = "Sorry you can't make it";

}

break;

case 2:

if(rsvp){

option1 = "Thanks for attending. You will be served chicken.";

} else{

option1 = "Sorry you can't make it";

}

break;

case 3:

if(rsvp){

option1 = "Thanks for attending. You will be served pasta.";

} else{

option1 = "Sorry you can't make it";

}

break;

default:

if(rsvp){

option1 = "Thanks for attending. You will be served fish.";

} else{

option1 = "Sorry you can't make it";

}

break;

}

(d) if (option1.equals(option2)){

System.out.println("True");

} else {

System.out.println("False");

}

Explanation:

This code is written in Java.

a) It uses an if statement to print "attending" if rsvp evaluates to true and "not attending" if rsvp is false.

b) An if-else structure determines which food choice is printed depending on user input. If selection equals 1, beef is printed; if it is 2, chicken appears; if it is 3, pasta is displayed; any other value results in fish being printed.

c) The switch statement checks the value of selection and uses an inner if statement to assign "Thanks for attending. You will be served beef." to option1 if rsvp is true. This assignment varies with the selection's value. When rsvp is false, option1 gets the message "Sorry you can't make it."

d) An if statement evaluates whether option1 and option2 are equivalent and outputs true if they match; otherwise, it indicates false.

8 0
1 month ago
Andre is finding working in an online group challenging because there are people in the group from many different cultural backg
Harlamova29_29 [926]

Answer:

Varied Communication Styles

Diverse Attitudes Toward Conflict

Different Methods for Completing Tasks

Various Decision-Making Approaches

Different Perspectives on Disclosure

Diverse Ways of Knowing

Explanation:

6 0
25 days ago
Read 2 more answers
If a packet gets “sucked down a black hole” (figuratively speaking) and is not received by its sender, and no message is sent ba
Harlamova29_29 [926]

If a packet gets figuratively “sucked into a black hole” and is not received by the original sender, with no message returned to clarify the situation, there is an issue. This lack of communication indicates there is a problem with the _____.

A.) ICMP

B.) TCP/IP

C.) HTTP

D.) ISO

A.) ICMP

I hope this information is useful and wish you the best.

~May

0 0
1 month ago
Use the following data definitions data myBytes BYTE 10h,20h,30h,40h myWords WORD 3 DUP(?),2000h myString BYTE "ABCDE" What will
Natasha_Volkova [897]

Answer:

Given Data:

myBytes BYTE 10h, 20h, 30h, 40h

myWords WORD 3 DUP(?), 2000h

myString BYTE "ABCDE"

From the supplied information, we can derive that:

(a).     a. EAX = 1

         b. EAX = 4

         c. EAX = 4

         d. EAX = 2

         e. EAX = 4

         f. EAX = 8

         g. EAX = 5

8 0
18 days ago
On a typical microprocessor, a distinct I/O address is used to refer to the I/O data registers and a distinct address for the co
maria [879]

Answer:

First I/O instruction format -> 256 ports

Second I/O instruction format -> 65536 ports

Explanation:

  • The initial instruction format can address 256 ports, computed from eight bits for port addressing as 2^8 = 256 ports.
  • The second instruction format allows for 65536 ports, which can be calculated using sixteen bits for addressing as 2^16 = 65536 ports.

Changing the opcode facilitates the selection between the first and second instruction format, allowing one input or output operation at a given moment.

5 0
24 days ago
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