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zloy xaker
1 month ago
13

Rework problem 4 from section 3.2 of your text, involving sets E and F. Suppose for this problem that Pr[E]=1/12, Pr[F]=1/12, an

d Pr[E∩F′]=0/1
1) What is Pr[E|F]?
2) What is Pr[F|E]?

Mathematics
1 answer:
Inessa [12.5K]1 month ago
3 0
The corresponding Venn Diagram for this issue is depicted below

P(E|F) and P(F|E) denote the conditional probabilities.

P(E|F) is calculated as P(E∩F) ÷ P(F) = ¹/₂ ÷ ¹/₂ = 1
P(F|E) is determined by P(F∩E) ÷ P(E) = ¹/₂ ÷ ¹/₂ = 1

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(1 point) Since 1966, 45% of the No. 1 draftpicks in the NBA have been centers. identify the population A. all No.1 draftpick ce
Zina [12379]

Response:

1 B

2 A

3 B

Detailed explanation:

1

The population refers to the entire sample from which part of the event is being analyzed. Essentially, in a set, the population includes everything collectively. From the provided statement, our goal is to identify the population. The population is B.

All NBA players since 1966. This selection is because it is from this set that the draft picks were chosen, ultimately narrowed down to 45% being center backs.

2

The specified attribute is A.

Being a No. 1 draft pick, as it's the central focus of the statement itself

3

B sample proportion. As mentioned earlier, the population consists of all NBA players since 1966, so a population proportion would contain a statement like this.

45% of all NBA players since 1966...

Consequently, it's a sample proportion since it pertains to the draft pick, as opposed to the NBA players

6 0
24 days ago
one day, the state fair total attaendance was 126,945. Round to the nearest hundred thousand, nearest ten thousand and nearest t
zzz [12365]
Nearest hundred thousand: 100,000

Nearest ten thousand: 130,000

Nearest thousand: 127,000

The amount that is closest to the actual attendance is 127,000 when rounded to the nearest thousand.
6 0
1 month ago
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If A(x1, y1), B(x2, y2), C(x3, y3), and D(x4, y4) form two line segments, and , which condition needs to be met to prove ?
Zina [12379]
The answer
the full question is
If A(x1, y1), B(x2, y2), C(x3, y3), and D(x4, y4) create two line segments, and AB ⊥ CD, what condition must be satisfied to establish that AB ⊥ CD?

Let A(x1, y1) and B(x2, y2) represent the first line, while C(x3, y3) and D(x4, y4) represent the second line.

The slope for the first line is given by m = (y2 - y1) / (x2 - x1).
For the second line, the slope is m' = (y4 - y3) / (x4 - x3).

The necessary condition to demonstrate that AB ⊥ CD is

                           
                    (y2 - y1) * (y4 - y3)
m × m' =  ---------  ×  ------------ = -1
                    (x2 - x1)    (y4 - y3)
5 0
1 month ago
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10 times as many as blank hundreds or 60 hundreds is blank thousands
Svet_ta [12734]

The result of multiplying 10 by 6 hundreds equals 60 hundreds, which can also be expressed as 6 thousands.

Explanation

This can be simplified as follows:

  • 10 times a given quantity of _____ hundreds results in 60 hundreds
  • 60 hundreds convert to _____ thousands

We will divide this into two segments:

\boxed{ \ 10 \times (N \times 100) = 60 \times 100 \ }... Equation-1

\boxed{ \ 60 \times 100) = M \times 1,000 \ }... Equation-2

This straightforward multiplication relates to the place value system. We need to perform calculations to find the values of N and M.

Initially, let's focus on Equation-1.

We will move the variable M to one side of the equation in order to isolate it and solve for its value.

\boxed{ \ 10 \times (N \times 100) = 60 \times 100 \ }

\boxed{ \ 1,000 \times N = 6,000 \ }

Both parts will be divided by 1,000, essentially being multiplied by \frac{1}{1,000}.

\boxed{ \ \frac{1}{1,000} \times 1,000 \times N = \frac{1}{1,000} \times 6,000 \ }

Thus, we conclude with \boxed{\boxed{ \ N = 6 \ }}

Next, we process Equation-2 to derive M's value.

\boxed{ \ 60 \times 100) = M \times 1,000 \ }

\boxed{ \ 6,000 = M \times 1,000 \ }

Rearranging this equation to place M on the left side appears as follows:

\boxed{ \ M \times 1,000 = 6,000 \ }

Again, both sides undergo division by 1,000, which translates to multiplication by \frac{1}{1,000}..

\boxed{ \ \frac{1}{1,000} \times M \times 1,000 = \frac{1}{1,000} \times 6,000 \ }

This results in \boxed{\boxed{ \ M = 6 \ }}

- - - - - - -

Alternative approach for the second step:

60 hundreds equals to __ thousands

\boxed{ \ 6 \times 10 \ hundreds = \ M \ thousands} \ }

\boxed{ \ 6 \times thousands = \ M \ thousands} \ }

\boxed{\boxed{ \ M = 6 \ }}

Additional resources

  1. A more detailed version of this topic
  2. 2 thousands 7 tens divided by 10 equals what?
  3. 100 is equivalent to 1/10 of which number?

Keywords: 10 times as many as, blank, hundreds, 60 hundreds, or, thousands, isolate, operations, multiply, divide, fraction, both sides, equal, the opposite, both sides are multiplied by, divided by, rearrange

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1 month ago
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Anya found the slope of the line that passes through the points (–7, 4) and (2, –3). Her work is shown below. Let (x2, y2) be (–
AnnZ [12381]
C. Anya employed an incorrect formula. The correct formula must reflect the change in the y-values in relation to the change in the x-values.
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