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Roman55
14 days ago
7

Consider the system: y = 3x + 5 y = ax + b What values for a and b make the system inconsistent? What values for a and b make th

e system consistent and dependent? Explain.
Mathematics
2 answers:
Svet_ta [4.3K]14 days ago
7 0
<span>The system becomes inconsistent when a equals 3 but b is not 5, as this results in parallel lines. If a equals 3 and b equals 5, the system is both consistent and dependent, since both equations represent the same line.</span>
Svet_ta [4.3K]14 days ago
3 0

Answer:

When a equals 3 and b is anything other than 5, the system does not have a solution because the lines are parallel. If a equals 3 and b equals 5, the system has infinitely many solutions because the two equations describe the same line.

Step-by-step explanation:

Reference: edg 2020

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Which is the solution of the quadratic equation (4y – 3)2 = 72? y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction a
Inessa [3926]

Answer:

y = \frac{3 + 6\sqrt{2} }{4} y y = \frac{3 - 6\sqrt{2} }{4}

y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction y = StartFraction 3 menos 6 StartRoot 2 EndRoot Over 4 EndFraction

Explicación paso a paso:

La ecuación cuadrática que tenemos es (4y - 3)² = 72

Debemos encontrar el valor de y.

Ahora, 4y - 3 = ± 6√2

⇒ 4y = 3 ± 6√2

⇒ y = \frac{3 + 6\sqrt{2} }{4} y y = \frac{3 - 6\sqrt{2} }{4}

Por lo tanto, las soluciones son y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction y y = StartFraction 3 menos 6 StartRoot 2 EndRoot Over 4 EndFraction (Respuesta)

6 0
11 days ago
Read 2 more answers
What are three different ways to make the number 15,638 with only hundreds, tens, and ones?
zzz [4035]
I think it’s 156 hundreds, 3 tens, and 8 ones.
3 0
18 days ago
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Which would best display the following data if you wanted to display the numbers which are outliers as well as the mean? [4, 1,
AnnZ [3900]

Organizing the data in increasing order to find the outlier and compute the mean

Detailed explanation:

The provided data consists of: [4, 1, 3, 10, 18, 12, 9, 4, 15, 16, 32]

Arranging it in ascending sequence

                               [1, 3, 4, 4, 9, 10, 12, 15, 16, 18, 32 ]

The outlier is identified as 32

Calculating the mean;

Mean=total of data set/quantity of data set

Total= 1 + 3+ 4+ 4+ 9+ 10+ 12+ 15+ 16+ 18+ 32=124

Quantity of data set=11

Mean=124/11=11.27

3 0
17 days ago
Venetta buys 2 pounds of pistachios and 3 pounds of almonds. The pistachios cost $4 more per pound than the almonds. She pays a
babunello [3666]

Answer:

A. Combining one pound of pistachios with one pound of almonds costs $20.

C. Decreasing the almond quantity by one pound leads to a total price of $40.

E. The price p (in dollars) per pound of pistachios is represented by the equation 2p + 3(p – 4) = 48.

Step-by-step explanation:

Let:

x = cost per pound of pistachios

y = cost per pound of almonds

We know that

x = y + 4 (Equation A)

2x + 3y = 48 (Equation B)

Substitute x from Equation A into Equation B:

2(y + 4) + 3y = 48

2y + 8 + 3y = 48

5y = 48 – 8

y = 8

Find x:

x = 8 + 4 = 12

Therefore, pistachios cost $12 per pound and almonds cost $8 per pound.

Verify the statements:

Case A) One pound of each equals $20.

True, since 12 + 8 = 20.

Case B) Pistachios cost twice as much as almonds.

False, because 2 × 8 = $16 ≠ $12.

Case C) Reducing almond pounds by 1 yields $40 total.

True, as 2(12) + 2(8) = 24 +16 = 40.

Case D) The almond cost modeled by 2(a – 4) + 3a = 48.

False; it should be 2(a + 4) + 3a = 48.

Case E) The pistachio cost modeled by 2p + 3(p – 4) = 48.

True, since p = a + 4 implies a = p – 4.

8 0
15 days ago
Identify the equation of the circle that has its center at (-27, 120) and passes through the origin.
zzz [4035]

The equation representing the circle centered at (-27, 120) that passes through the origin is:

(x + 27)^2 + (y - 120)^2 = 15129

Solution:

The general equation of a circle is expressed as:

(x-a)^2+(y-b)^2=r^2

Where,

(a, b) denotes the center of the circle

r signifies the radius

Given the center as (-27, 120)

Thus;

a = -27

b = 120

Considering it intersects the origin, meaning (x, y) = (0, 0)

Substituting (a, b) = (-27, 120) and (x, y) = (0, 0) into the equation

(0 + 27)^2 + (0 - 120)^2 = r^2\\\\729 + 14400 = r^2\\\\r^2 = 15129

Input r^2 = 15129 and (a, b) = (-27, 120) into the equation

(x + 27)^2 + (y - 120)^2 = 15129

Hence, the equation characterizing the circle is determined

6 0
6 days ago
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