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DanielleElmas
1 month ago
9

Compare 36% of 2.5b  and 1.5% of 80b

Mathematics
1 answer:
zzz [12.3K]1 month ago
7 0
<span>0.9 is 36% of 2.5b  


1.2 is 1.5% of 80b

1.2 is greater than 0.9</span>
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The probability that a customer's order is not shipped on time is 0.06. A particular customer places three orders, and the order
AnnZ [12381]

Response:

a)

b) 0.044

Step-by-step breakdown:

Part a)

A Sonet consists of 14 lines. Raymond Queneau published a collection of 10 sonnets, each placed on separate pages. This implies that every page contains a 14-line poem. We are to determine how many unique sonnets can be created from the 10 published sonnets.

As the first line of a new sonnet can be chosen from any of the 10 published sonnets, it offers 10 options for the selection of the first line. Likewise, the second line of the new sonnet can also be from any of the 10 sonnets, leading to another 10 choices for the second line, and this applies identically for all 14 lines, resulting in 10 options for each line.

According to the fundamental principle of counting, the total number of possible sonnets would equal the product of the options available for all 14 lines.

Thus,

the number of sonnets created from those in the book = 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 =

sonnets

Therefore,

can be formed from the 10 in the book.

Part b)

Next, we will ascertain how many sonnets can be generated that utilize none of the lines from the first and last page. Given that there are 10 pages total, the exclusion of the 1st and last leaves us with 8 pages (8 sonnets).

Consequently, the number of options for each line of such a sonnet will be restricted to 8 choices. Applying the fundamental principle of counting, the total sonnets with no lines from either the first or last sonnet is calculated as

P = (0.94)^{3}

This shows the number of favorable outcomes that ensure the selection of a sonnet does not result in lines from the first or last sonnet in the collection.

Thus,

The probability that no lines are selected from either the first or the last sonnet =

5 0
1 month ago
A rope, attached to a weight, goes up through a pulley at the ceiling and back down to a worker. The worker holds the rope at th
Leona [12618]

Answer:0.246 ft/s

Step-by-step explanation: As the worker starts moving and stops 10 feet away from the side rope connected to the load, it creates a right triangle, as illustrated in the image.

V = s/t... equation 1

S = distance the worker travels while pulling the rope = 10 ft

V = worker's velocity = 2 ft/s

T = time it takes for the worker to cover 10 ft = the same time the load takes to rise = 5 seconds

Using Pythagorean theorem to find the distance from the pulley to the new position of the worker

Square root of (40^2 + 10^2) = 41.23 ft

Distance covered by load = D = 41.23 - 40

= 1.23 ft

Load speed = D/t...equation 2

Substituting D and t into equation 2 gives us

Load speed = 1.23/5 = 0.246 ft/s

4 0
20 days ago
C) Your parents have been advised to save 5% of their income for your college education
Svet_ta [12734]

48,948 * 5% = 2447.4

7 0
1 month ago
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When jumping, a flea rapidly extends its legs, reaching a takeoff speed of 1.0 m/s over a distance of 0.50 mm . part a what is t
zzz [12365]

The flea experiences an acceleration of 1,000 m/s².

Detailed explanation

This scenario involves motion with constant acceleration.

The relevant variables include the following.

\boxed{u \ or \ v_i = initial \ velocity}

\boxed{u \ or \ v_t \ or \ v_i = terminal \ or \ final \ velocity}

\boxed{a = acceleration \ (constant)}

\boxed{d = distance \ travelled}

We know the flea attains a takeoff velocity of 1.0 m/s over a distance of 0.50 mm.

The flea starts from rest, so the initial velocity is zero. The question asks for the flea's acceleration during leg extension.

The equation we apply is:

\boxed{ \ v^2 = u^2 + 2ad \ }

  • a = acceleration (m/s²)
  • u = initial speed = 0 m/s
  • v = takeoff velocity = 1.0 m/s
  • d = displacement = 0.50 mm

First, convert 0.50 mm to meters: \boxed{0.50 \ mm = 0.50 \times 10^{-3} \ m = 5.0 \times 10^{-4} \ m}

Solution steps:

Rearrange the formula to isolate acceleration (a).

\boxed{ \ v^2 = u^2 + 2ad \ }

\boxed{ \ v^2 - u^2 = 2ad \ }

\boxed{ \ 2ad = v^2 - u^2 \ }

\boxed{ \ a = \frac{v^2 - u^2}{2d} \ }

Insert the given values into the rearranged equation.

\boxed{ \ a = \frac{(1.0)^2 - (0)^2}{2(5.0 \times 10^{-4})} \ }

\boxed{ \ a = \frac{1}{10 \times 10^{-4}} \ }

\boxed{ \ a = \frac{1}{1 \times 10^{-3}} \ }

\boxed{ \ a = 1 \times 10^{3}\ = 1,000 \ m/s^2 \ }

This yields the flea's acceleration as 1,000 m/s².

Additional resources

  1. Scientific notation: brainly.com/question/7263463
  2. Determining substance mass: brainly.com/question/4053884
  3. Conversion into cubic units: brainly.com/question/1446243

Keywords: flea, jumping, leg extension, takeoff velocity, initial speed, displacement, acceleration, constant acceleration, unit conversion

5 0
2 months ago
Read 2 more answers
1. Which of the following is the first step in the licensing process?
Leona [12618]

I think the answer is A
Idnjnxjxnnxnndknxjnxjjd

3 0
2 months ago
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