Suppose that the height of the slide is 2 feet,

The correct answer is Option (D). The subtraction property of equality asserts that whatever is subtracted from one side of an equation must also be subtracted from the other side. In the instance where x + 2 = 2, applying this property leads to: x + 2 - 2 = 2 - 2, simplifying to x = 0. However, the provided question displays the addition property of equality utilized in step 2, indicating that the subtraction property was not applied there. Consequently, Option (D) is the correct response.

Answer:

Step-by-step explanation:

Considering the equation

Sin(5x) = ½

5x = arcSin(½)

5x = 30°

Then,

The general formula for sin is

5θ = n180 + (-1)ⁿθ

Dividing throughout by 5

θ = n•36 + (-1)ⁿ30/5

θ = 36n + (-1)ⁿ6

The solution range is

0<θ<2π which means 0<θ<360

First solution

When n = 0

θ = 36n + (-1)ⁿθ

θ = 0×36 + (-1)^0×6

θ = 6°

When n = 1

θ = 36n + (-1)ⁿ6

θ = 36-6

θ = 30°

When n = 2

θ = 36n + (-1)ⁿ6

θ = 36×2 + 6

θ = 78°

When n =3

θ = 36n + (-1)ⁿ6

θ = 36×3 - 6

θ = 102°

When n=4

θ = 36n + (-1)ⁿ6

θ = 36×4 + 6

θ = 150

When n=5

θ = 36n + (-1)ⁿ6

θ = 36×5 - 6

θ = 174°

When n = 6

θ = 36n+ (-1)ⁿ6

θ = 36×6 + 6

θ = 222°

When n = 7

θ = 36n + (-1)ⁿ6

θ = 36×7 - 6

θ = 246°

When n =8

θ = 36n + (-1)ⁿ6

θ = 36×8 + 6

θ = 294°

When n =9

θ = 36n + (-1)ⁿ6

θ = 36×9 - 6

θ = 318°

When n =10

θ = 36n + (-1)ⁿ6

θ = 36×10 + 6

θ = 366°

When n = 10 surpasses the θ range

Thus, the solutions range from n =0 to n=9

Therefore, there are 10 solutions within the interval 0<θ<2π

Brent could represent a rectangle with the dimensions of x - 1 and x - 6, then demonstrate that the area equals the combination of x^2, -x, -6x, and 6.

Answer:

The distance from the point (0,1,1) to the specified line is zero.

Step-by-step explanation:

Considering the parametric equations of the line,

x=2t, y=5-2t, z=1+t

In order to calculate the distance from (0,1,1), we must remove t from the equations above, such that

whose direction ratios are (l,m,n)=(3,2,-2) and the distance from point (a,b,c)=(0,1,1) is defined as

The distance between the point (0,1,1) and (1) amounts to zero. Therefore, the point (0,1,1) is located on the line (1).

Response:

Detailed explanation:

The final result is 3 /8/33.

step by step breakdown

Initially, we write:

x

=

3

.

¯¯¯¯

24

After that, we will multiply each side by

100

leading to:

100

x

=

324

.

¯¯¯¯

24

Subsequently, we will subtract the first equation from the second equation:

100

x

−

x

=

324

.

¯¯¯¯

24

−

3

.

¯¯¯¯

24

We can then solve for

x

in the following manner:

100

x

−

1

x

=

(

324

+

0

.

¯¯¯¯

24

)

−

(

3

+

0

.

¯¯¯¯

24

)

(

100

−

1

)

x

=

324

+

0

.

¯¯¯¯

24

−

3

−

0

.

¯¯¯¯

24

99

x

=

(

324

−

3

)

+

(

0

.

¯¯¯¯

24

−

0

.

¯¯¯¯

24

)

99

x

=

321

+

0

99

x

=

321

99

x

99

=

321

99

99

x

99

=

3

×

107

3

×

33

x

=

3

×

107

3

×

33

x

=

107

33

Next, we convert this improper fraction to a mixed numeral:

x

=

107

33

=

99

+

8

33

=

99

33

+

8

33

=

3

+

8

33

=

3

8

33

3

.

¯¯¯¯

=

3

8

33