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Natasha2012
2 months ago
6

***Photo Attached***

Mathematics
2 answers:
tester [12.3K]2 months ago
8 0

Answer

Jill

Solution

The diagram associated with this question illustrates the performance of five educators at Oakdale middle school.

It presents a chart spanning five years (2005 - 2009).

The teachers are Jill, Ed, Ralph, Tina, and Sam. Initially examining Jill’s results, her performance fluctuated only in 2006 while remaining steady during all other years. In contrast, the other teachers showed inconsistent performance trends.

Thus, Jill displayed the most stable performance over the five-year period

tester [12.3K]2 months ago
5 0
In my opinion, the correct response is jill
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Brandon purchased a new guitar in 2012. The value of his guitar, t years after he bought it, can be modeled by the function A(t)
Zina [12379]

Answer: The guitar's value over time is described by the 0.95 metric, indicating a 5% annual depreciation.

Step-by-step explanation:

To address this inquiry, we use an exponential decay formula:

A = P (1 - r) t

Where:

P = initial price

r = the reduction rate (expressed as a decimal)

t = time in years

A = price after t years

Substituting the known values:

A(t)=145(0.95)t.

Where

0.95 = 1-r

0.95-1 = r

-0.05 = -r

0.05 = r

Converted to percentage:

0.05 x 100 = 5%

Please reach out if further clarification is needed or if something was unclear.

6 0
3 months ago
Jonathan has 3/4 pound of grapes.how many 1/8pound servings can Jonathan make from his grapes
Inessa [12570]

Response:

6 servings.

Detailed explanation:

To determine this, divide 3/4 by 1/8, here are the steps:

3/4 divided by 1/8

3/4 times 8/1

(3 × 8 = 24); (4 × 1 = 4)

24 divided by 4 results in 6.

I hope this assists! If possible, please grant me brainliest, as I need it to level up! Thank you.

5 0
2 months ago
Find the values of x1 and x2 where the following two constraints intersect.
Inessa [12570]

Answer: x1 = 251/26, x2 = -111/26

Step-by-step explanation:

Greetings!

As illustrated in the diagram, the point you seek is where the two lines intersect.

This intersection point is found by solving the system of linear equations (both equations must be satisfied by the point):

9x_1 +7x_2=57\\4x_1 + 6x_2 = 13

You can approach solving it using the substitution method:

\text{solve for x1 in the first equation:}\\x_1 = \frac{1}{9}(57 - 7x_2)

Then substitute x1 into equation 2 to resolve x2:

\frac{4}{9}(57-7x_2) + 6x_2 = 13\\\text{doing the algebra you get:}\\x_2 = \frac{-111}{26}

After which, utilize the x2 value to establish x1:

x_1 = \frac{1}{9}(57 - 7x_2)= \frac{1}{9}(57 + 7*\frac{111}{26}) = 251/26\\

4 0
2 months ago
Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probab
Svet_ta [12734]

Response:  a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

Detailed explanation:

In Problem 8-4, the computer time-sharing system experiences teleport inquiries at an average rate of 0.1 per millisecond. We are tasked with determining the probabilities of the inquiries over a specific period of 50 milliseconds:

Given that

\lambda=0.1\ per\ millisecond=5\ per\ 50\ millisecond=5

Applying the Poisson process, we find that

(a) at most 12

probability=  P(X\leq 12)=\sum _{k=0}^{12}\dfrac{e^{-5}(-5)^k}{k!}=0.9980

(b) exactly 13

probability= P(X=13)=\dfrac{e^{-5}(-5)^{13}}{13!}=0.0013

(c) more than 12

probability= P(X>12)=\sum _{k=13}^{50}\dfrac{e^{-5}.(-5)^k}{k!}=0.0020

(d) exactly 20

probability= P(X=20)=\dfrac{e^{-5}(-5)^{20}}{20!}=0.00000026

(e) within the range of 10 to 15, inclusive

probability=P(10\leq X\leq 15)=\sum _{k=10}^{15}\dfrac{e^{-5}(-5)^k}{k!}=0.0318

Thus, a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

6 0
2 months ago
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