Answer:
(A) 0.15625
(B) 0.1875
(C) Cannot be determined
Step-by-step explanation:
The time it takes for a student to finish a statistics quiz is uniformly distributed between 32 and 64 minutes.
Let's denote X as the duration needed for the student to complete the statistics quiz
Thus, X ~ U(32, 64)
The probability density function (PDF) for a uniform distribution is expressed as;
f(X) = 
, a < X < b where a = 32 and b = 64
The cumulative distribution function (CDF) is given by P(X <= x) = 
(A) The probability of a student taking longer than 59 minutes to complete the quiz = P(X > 59)
P(X > 59) = 1 - P(X <= 59) = 1 - = 1 - 
= 
= 0.15625
(B) The probability that a student completes the quiz between 37 and 43 minutes = P(37 <= X <= 43) = P(X <= 43) - P(X < 37)
P(X <= 43) = 
= 
= 0.34375
P(X < 37) = 
= 
= 0.15625
P(37 <= X <= 43) = 0.34375 - 0.15625 = 0.1875
(C) The probability that a student takes exactly 44.74 minutes to complete the quiz
= P(X = 44.74)
This probability cannot be calculated as it is a continuous distribution, which doesn't provide probabilities for specific points.
Answer:
Attached is the question in consideration.
forms a straight line.
depicts a right triangle.
The options 
represent the correct answers.
Step-by-step explanation:
⇒ Given that 
is ⊥
it constitutes a right triangle, leading to 
.
⇒ The measure for 
equals 
as 
bisects 
, implying that is half of , thus 
.
⇒ represents a straight line, as the angle measures across it yield 
.
⇒ The angle measure for 
is derived from the linear pair concept.
Since
, inserting the values of
leads to
.
The other two options are incorrect as:
it surpasses while is a
straight line.
- Also,
is inaccurate.
As 
and 
Thus, we have a total 
valid answers.
The confirmed options are .
The provided values are
$85 $240 $120 $60 $315 $190 $145 $105 $285 $260 $95 $215 $235 $175 $155
To start, we will arrange these in ascending order
resulting in
$60 $85 $95 $105 $120 $145 $155 $175 $190 $215 $235 $240 $260 $285 $315
The total count is 15
the position of 105 is 4
Now, we can calculate the percentile
Thus, the percentile for the bid of $105 is 26.667%...........Response
Answer:
Hello! Your question appears to be missing details; here is the complete version
Ix = 0 Ux = 
Iz = 0 Uz = 
Iy = 5 Uy = 10
Step-by-step explanation:
Ix = 0 Ux =
Iz = 0 Uz =
Iy = 5 Uy = 10
This provides a comprehensive solution below
Answer:
The remaining area available for construction is 
Step-by-step analysis:
The inquiry in English reads
The total area of a property, measured in square meters, amounts to 704/5. A house is constructed occupying 5/6 of this area. Half of the leftover space is utilized for a terrace; thus, how much area remains for additional construction?
We know that
The total area is represented by the fraction 6/6
A house accounts for 5/6 of the entire area
Thus, the remaining area is (6/6)-(5/6)=1/6 of the overall area
If half of this leftover area is designated for a terrace
then
the terrace occupies (1/6)/2=1/12 of the total area
consequently,
The area remaining for construction is 1/12 of the total area
therefore
