Answer:
Step-by-step explanation:
Hello!
To find the total length when it is 18 feet 3 inches, we must add both lengths:
18ft 3in + 18ft 3in = 36ft 6in
For the width, add: 10ft 8in + 10ft 8in = 20ft 16in, which converts to 21ft 4in
Therefore, l + w = 57ft 10in
I hope this is helpful:)
The function in vertex form is evaluated to be.
5q + 2d = 270
To determine the intercepts, start by setting d to 0, then to find q. The conditions yield:
5q = 270
q = 54; (0, 54)
2d = 270
d = 135; (135, 0)
This equation illustrates the total number of coins in the piggy bank. For (0, 54), this indicates the quantity of quarters when dimes are absent, while (0, 135) displays the number of dimes when there are no quarters.
Response:
the expected value of this raffle if you purchase 1 ticket = -0.65
Breakdown of the calculation:
Details:
5,000 tickets are sold at $1 each for a charitable raffle
Winners will be chosen at random with cash prizes as follows: 1 prize of $500, 3 prizes of $300, 5 prizes of $50, and 20 prizes of $5.
Therefore, the value and its respective probability can be calculated as follows:
Value Probability
$500 - $1 = $499 1/5000
$300 - $1 = $299 3/5000
$50 - $1 = $49 5/5000
$5 - $1 = $4 20/5000
-$1 1 - 29/5000 = 4971/5000
The expected value of the raffle when buying 1 ticket is computed as follows:
So, the expected value of this raffle when one ticket is purchased = -0.65
To derive the function that characterizes the bee population:
1) Initially, there are 9,000 bees in the first year.
2) In the second year, a reduction of 5% occurs => 9,000 - 0.05 * 9,000 = 9,000 * (1 - 0.05) = 9,000 * 0.95
3) Each subsequent year sees a 5% decline => 9,000 * (0.95)^(number of years)
4) Let x represent years and f(x) signify the bee count, then: f(x) = 9,000 (0.95)^x.
Evaluation of the claims:
<span>1) The function f(x) = 9,000(1.05)x applies to the scenario.
FALSE: WE ESTABLISHED IT AS f(x) = 9,000 (0.95)^x
2) The function f(x) = 9,000(0.95)x applies to the scenario.
TRUE: THIS IS THE RESULT OF OUR PRIOR ANALYSIS.
3) After 2 years, the farmer projects approximately 8,120 bees will be left.
Calculating:
f(2) = 9,000 * (0.95)^2 = 9,000 * 0.9025 = 8,122
Thus, this statement is TRUE
4) After 4 years, the farmer can predict there will be roughly 1,800 bees left.
f(4) = 9,000 * (0.95)^4 = 9,000 * 0.81450625 = 7,330
This statement is therefore FALSE
5) The domain values contextual to this situation are restricted to whole numbers.
FALSE: DOMAIN VALUES INCLUDE ALL NON-NEGATIVE REAL NUMBERS. FOR INSTANCE, THE FUNCTION IS VALID AT X = 5.5
6) The range values pertinent to this situation are restricted to whole numbers.
TRUE: FRACTIONS OF BEES CANNOT EXIST.
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