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10 days ago

8

One winter day, the outside temperature, y, was never below −1°. The inside of a car was always warmer than the temperature outs

ide by at least 4°. Which graph of a system of inequalities represents this scenario?

2 answers:

zzz [9K]10 days ago

6 0

Respuesta:

c

Explicación paso a paso:

Leona [9.2K]10 days ago

4 0

Respuesta: Es C

Explicación paso a paso:

Tu gráfico debe ser este, con ambas líneas sólidas, dado que la línea X, o roja, debe estar al menos en -1 o más, y la línea Y, o azul, debe estar en +4 o más

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g European roulette. The game of European roulette involves spinning a wheel with 37 slots: 18 red, 18 black, and 1 green. A bal

Leona [9271]

Answer:

The total expected value and standard deviation of your winnings are -$0.081 and $3, respectively.

Step-by-step explanation:

In European roulette, a wheel with 37 slots is spun: 18 are red, 18 are black, and 1 is green.

Bettors can wager on either red or black. Winning on their chosen color means they double their bet, while losing means they forfeit their stake.

Define the probability for the ball landing in a red slot = $\frac{18}{37}$

The probability of it landing in a black slot = $\frac{18}{37}$

The probability for landing in the green slot = $\frac{1}{37}$

Since bets are only placed on red or black,

The winning probability = $\frac{18}{37}$

and losing probability = $\frac{18}{37}+\frac{1}{37}$

= $\frac{19}{37}$

If a gambler wins, they receive $3, and if they lose, it amounts to -$3.

The expected value of the total winnings is hence;

E(X) = $\sum X \times P(X)$

= $\$3 \times \frac{18}{37} + (-\$3 \times \frac{19}{37})$

= $\$3 \times (-\frac{1}{37})$ = -$0.081

Furthermore, the standard deviation of the total winnings is given by;

S.D.(X) = $\sqrt{(\sum X^{2} \times P(X))-(\sum X \times P(X))^{2} }$

<pTherefore, $E(X^{2})=\sum X^{2} \times P(X)$

= $\$3^{2} \times \frac{18}{37} + (-\$3^{2} \times \frac{19}{37})$

= $\$9 \times (\frac{18}{37}+\frac{19}{37})$ = $9

Thus, S.D.(X) = $\sqrt{\$9-(-\$0.081)^{2} }$

= $\sqrt{8.993}$ = $2.99 ≈ $3

Consequently, the anticipated value and standard deviation of your total winnings are -$0.081 and $3, respectively.

6 0

1 month ago

Jonathan has 3/4 pound of grapes.how many 1/8pound servings can Jonathan make from his grapes

Inessa [9000]

Response:

6 servings.

Detailed explanation:

To determine this, divide 3/4 by 1/8, here are the steps:

3/4 divided by 1/8

3/4 times 8/1

(3 × 8 = 24); (4 × 1 = 4)

24 divided by 4 results in 6.

I hope this assists! If possible, please grant me brainliest, as I need it to level up! Thank you.

5 0

12 days ago

A battery with 20% percent of its full capacity is connected to a charger. Every minute that passes, an additional 5% percent of

Inessa [9000]

Response:

The connection between battery capacity and time is:

$Y=0.05t+0.2$

The associated graph is provided.

Step-by-step explanation:

We will plot the battery's charged capacity against time.

The charging rate remains steady; hence, the relationship is linear.

Initially, at time t=0, the battery's capacity measures 0.2 (or 20%).

With each passing minute, an additional 5% of its capacity is accumulated. Thus, at t=1, the capacity becomes 0.2 + 0.05 = 0.25 (or 25%).

We can derive the slope for the linear function as:

$m=\dfrac{\Delta Y}{\Delta t}=\dfrac{0.05}{1}=0.05$

Consequently, the correlation between battery capacity and time is:

$Y=0.05t+0.2$

3 0

7 days ago

In isosceles △ABC (AC = BC) with base angle 30° CD is a median. How long is the leg of △ABC, if sum of the perimeters of △ACD an

Leona [9271]

Important details about isosceles triangle ABC:

The median CD, which is drawn to the base AB, also acts as an altitude to that base in the isosceles triangle (CD⊥AB). This indicates that triangles ACD and BCD are congruent right triangles, each with hypotenuses AC and BC.
In isosceles triangle ABC, the sides AB and BC are equal, meaning AC=BC.
The base angles at AB are equal, m∠A=m∠B=30°.

1. Consider the right triangle ACD. The angle adjacent to side AD is 30°, which dictates that the hypotenuse AC is double the length of the opposite side CD relating to angle A.

AC=2CD.

2. Now, for right triangle BCD, the angle next to side BD is also 30°, so hypotenuse BC is twice the opposite leg CD linked to angle B.

BC=2CD.

3. To calculate the perimeters of triangles ACD, BCD, and ABC:

$P_{ACD}=AC+CD+AD=2CD+CD+AD=3CD+AD;$

$P_{BCD}=BC+CD+BD=2CD+CD+AD=3CD+AD;$

$P_{ABC}=AC+BC+AB=2CD+2CD+AD+BD=4CD+2AD.$

4. If the total of the perimeters of triangles ACD and BCD is 20 cm greater than the perimeter of triangle ABC, then

$P_{ACD}+P_{BCD}=P_{ABC}+20,\\ \\3CD+AD+3CD+AD=4CD+2AD+20,\\ \\6CD+2AD=4CD+2AD+20,\\ \\2CD=20.$

5. Given that AC=BC=2CD, the lengths of legs AC and BC of the isosceles triangles are 20 cm.

Answer: 20 cm.

8 0

17 days ago

Read 2 more answers

1. X^4(dy/dx) +x^3y =- sec (xy)<br><br>Integral by separation of variables? <br>

PIT_PIT [9117]

Answer:

Step-by-step explanation:

Considering the differential equation x^4(dy/dx) + x^3y = -sec(xy). We will solve it employing the method of separation of variables;

$x^{4} \frac{dy}{dx} +x^{3}y = -sec(xy)\\x^{3}(x\frac{dy}{dx} + y) = -sec(xy)\\let \ v=xy\\\frac{dv}{dx} = x\frac{dy}{dx} + y(implicit \ in\ nature)\\$

By substituting v and dv/dx into the previous equation, we acquire;

$x^{3}\frac{dv}{dx} = -secv$

We then separate the variables:

$-\frac{dv}{secv} = \frac{dx}{x^{3} }$

$-cosvdv = x^{-3}dx\\ integrating\ both\ sides\\-\int\limits {cosv} \, dv = \int\limits {x^{-3} } \, dx\\-sinv = \frac{x^{-2} }{-2} + C\\since\ v = xy\\-sinxy = \frac{x^{-2} }{-2} + C\\2sin(xy) = x^{-2} -2C\\2 sin(xy) = \frac{1}{x^{2} } -K (where\ K = 2C)\\$

The end expression provides the solution to the differential equation.

8 0

27 days ago