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AleksAgata
2 months ago
5

According to TMUSS Quarterly (Totally Made-Up Sports Statistics) April 2017, the probability that the Tampa Bay Buccaneers will

score a touchdown on their opening drive is 0.14. The probability that their defense will have 3 or more sacks in the game is 0.31. The probability that the Bucs will either score a touchdown on their opening drive or have 3 or more sacks in the game is 0.14. What is the probability that they will both score a touchdown on the opening drive and have 3 or more sacks in the game?
Mathematics
1 answer:
tester [12.3K]2 months ago
7 0

Answer: 0.31

Step-by-step explanation:

Let A signifies the event of the Tampa Bay Buccaneers scoring a touchdown on their initial drive while B signifies the occurrence of their defense achieving 3 or more sacks during the game.

Given: P(A)=0.14     P(B) = 0.31     P(A or B)=0.14

Formula: P(A and B)= P(A) + P(B) - P(A or B)

Now, we calculate the probability of both scoring a touchdown on the initial drive and achieving 3 or more sacks in the game as follows:-

P(A and B)= 0.14 + 0.31 - 0.14=0.31

Therefore, the required probability is: 0.31

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