A kids skipping rope is 7ft long. How many ropes could I cut from a 10 yard long piece of rope?

Answer:

The area of the new pumpkin patch can be represented as    =  15 x² + 380 x + 2400

Step-by-step explanation:

Given as:

The length of the original patch is L = 40 meters

The width of the original patch is W = 60 meters

Thus, the area of the rectangular patch is calculated as Length × Width

Or, =  L × W

So,    =  40 meters × 60 meters

Or,   =  2400 meters²

Moreover, the width of the new patch becomes (40 + 3 x) meters

And the length of the new patch becomes (60 + 5 x) meters

Or,  =  L × W

Thus,  =  (40 + 3 x) meters × (60 + 5 x) meters

Or,    = 2400 + 200 x + 180 x + 15 x²

Or,    =  15 x² + 380 x + 2400

Therefore, the area of the new pumpkin patch is given by    =  15 x² + 380 x + 2400  Answer

Answer:

How much is the rent? And how many clothes does she want to buy?

Step-by-step explanation:

Answer:

The correct statements are;

1) ΔBCD is similar to ΔBSR

2) BR/RD = BS/SC

3) (BR)(SC) = (RD)(BS)

Step-by-step explanation:

1) Since RS is parallel to DC, we conclude that;

∠BDC = ∠BRS (Angles formed on the same side of the transversal)

Furthermore;

∠BCD = ∠BSR (Angles formed on the same side of the transversal)

∠CBD = ∠CBD (Reflexive property)

Thus;

ΔBCD ~ ΔBSR by the Angle-Angle-Angle (AAA) similarity criterion.

2) Given that  ΔBCD ~ ΔBSR, we obtain;

BC/BS = BD/BR → (BS + SC)/BS = (BR + RD)/BR = 1 + SC/BS = RD/BR + 1

1 + SC/BS = 1 + RD/BR thus, SC/BS = 1 + BR/RD - 1

SC/BS = RD/BR

By inverting both sides we find;

BR/RD = BS/SC

3) From BR/RD = BS/SC, we apply cross multiplication;

BR/RD = BS/SC leads to;

BR × SC = RD × BS → (BR)(SC) = (RD)(BS).