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2 months ago

15

Samuel rotated PLUTO 90° clockwise about the origin to generate P'L'U'T'O'.

1 answer:

tester [12.3K]2 months ago

5 0

Response:.

Detailed explanation:

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What is the logarithm of the equilibrium constant, log K, at 25°C of the voltaic cell constructed from the following two half-re

lawyer [12517]

Answer:

4.0921 reflects the logarithm of the equilibrium constant.

Step-by-step explanation:

$Fe^{2+} (aq) +2e^{-}\rightarrow Fe(s)$ ; E° = - 0.41 V

$Ag^+(aq) + e^-\rightarrow Ag(s)$ ; E° = 0.80 V

Iron has a negative reduction potential, indicating its tendency to lose electrons and undergo oxidation, and thus it will be at the anode.

$E^{o}_{cell}$ =Reduction potential of cathode - Reduction potential of anode

$E^{o}_{cell}=E^{o}_c-E^{o}_a$

$=0.80 V-(-0.41 V)=1.21 V$

$Fe^{2+} (aq) + 2e^{-}\rightarrow Fe(s)$ ; E° = - 0.41 V

$2Ag^+(aq) + 2e^-\rightarrow 2Ag(s)$ ; E° = 0.80 V

Net reaction: $Fe(s)+2Ag^{+}\rightarrow Fe^{2+}+2Ag(s)$

n = 2

To determine the equilibrium constant, we utilize the correlation with Gibbs free energy, as follows:

$\Delta G^o=-nfE^o_{cell}$

and,

$\Delta G^o=-RT\ln K_{eq}$

Aligning these two equations yields:

$nfE^o_{cell}=RT\ln K_{eq}$

where,

n = electrons transferred = 2

F = Faraday's constant = 96500 C

$E^o_{cell}$ = standard electrode potential of the cell = 1.21 V

R = gas constant = 8.314 J/K.mol

T = reaction temperature = $25^oC=[273+25]=298K$

Substituting values into the equation, we arrive at:

$2\times 96500\times 1.21 V=8.314\times 298\times \ln K_{eq}$

$\ln K_{eq}=9.3478$

$\log K_{eq}=\frac{9.3478}{2.303}=4.0921$

4.0921 represents the logarithm of the equilibrium constant.

7 0

2 months ago

If ABCD is a parallelogram, which of the following statements must be true?

lawyer [12517]

Answer: d. AB = CD and BC = AD

Step-by-step explanation:

A parallelogram is defined as a four-sided figure with the following characteristics:-

Opposite sides are equal (AB = CD and BC = AD ).
Opposite angles are equal (∠A=∠C and ∠D=∠B).
Consecutive angles are supplementary (∠A + ∠D = 180°).
The diagonals bisect one another.
If one angle is a right angle, then all angles are right angles.

8 0

2 months ago

Read 2 more answers

Nina can stitch 2/3 of a dress in 4 hours. If d represents the number of dresses and h represents the number of hours, which equ

tester [12383]

Response:

D=4 hours

Detailed explanation:

5 0

2 months ago

A restaurant purchased kitchen equipment on January 1, 2017. On January 1, 2019, the value of the equipment was $14 comma 550

babunello [11817]

Answer:

$\frac{dV(t)}{dt} =$ - 1675.38

Step-by-step explanation:

In 2017, the kitchen equipment's value was recorded at $14,550.

V(0)=$14550

Its following value is represented by $V(t)=14550e^{-0.158t$ .

We need to ascertain the rate of value change as of January 1, 2019.

$V(t)=14550e^{-0.158t$

$\frac{dV(t)}{dt} =\frac{d}{dt}14550e^{-0.158t$

$\frac{dV(t)}{dt} =14550 \frac{d}{dt}e^{-0.158t$

$\\Let u= -0.158t,\frac{du}{dt}=-0.158$

$\frac{dV(t)}{dt} =14550 \frac{d}{du}e^u\frac{du}{dt}$

$\frac{dV(t)}{dt} =14550 X -0.158 e^{-0.158t}=-2298.9e^{-0.158t}$

As of 2019, which is 2 years later, we set t=2.

The rate of value change is

$\frac{dV(t)}{dt} =-2298.9e^{-0.158X2}$

= $\frac{dV(t)}{dt} =-2298.9e^{-0.316}$ = -1675.38

3 0

2 months ago