Miguel buys a large bottle and a small bottle of juice. The amount of juice that the manufacturer puts in the large bottle is a
random variable with a mean of 1016 ml and a standard deviation of 8 ml. The amount of juice that the manufacturer puts in the small bottle is a random variable with a mean of 510 ml and a standard deviation of 5ml. If the total amount of juice in the two bottles can be described by a normal model, what’s the probability that the total amount of juice in the two bottles is more than 1540.2 ml?
Pr(X>1540.2) = 0.0655. Step-by-step explanation: The expected value indicated for the large bottle is E(Large) = 1016, and for the small bottle, E(small) = 510. This leads to an expected total E(total) = 1016 + 510 = 1526. The new mean calculated is thus 1526. To find the standard deviation, we derive the variance of each bottle. The variance for the large bottle is v(large) = 8^2 = 64, while for the small bottle it's v(small) = 5^2 = 25. Hence, the total variance is v(total) = 64+25 = 89, resulting in a new standard deviation sd(new) = sqrt(89) = 9.434. To find the probability, we compute using the new mean and standard deviation. The z score is derived as z = (x - mean)/sd = (1540.2 - 1526)/9.434 = 1.505. Looking up this z score gives P(z<1.51) = 0.9345. Consequently, for x > 1540.2, we have P(z > 1.51) = 1 - 0.9345 = 0.0655.
9. Observing the pattern, the decimal digit at position n is 9 when n is even and 0 when n is odd. Because 44 is an even number, the 44th digit after the decimal point is 9.
