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mafiozo
2 months ago
9

Consider △LNM. Triangle L M N is shown. Angle N M L is a right angle. Which statements are true for triangle LNM? Check all that

apply. The side opposite ∠L is NM. The side opposite ∠N is ML. The hypotenuse is NM. The hypotenuse is LN. The side adjacent ∠L is NM. The side adjacent ∠N is ML.

Mathematics
1 answer:
AnnZ [12.3K]2 months ago
3 0
The side opposite angle ∠L is named NM. The side opposite angle ∠N is named ML, while the hypotenuse is LN. To clarify, drawing even a rough sketch could assist in understanding this (see attached). Generally, a side across from an angle will not share the same designation as that angle. Conversely, a side adjacent to the angle will include the corresponding angle letter. Valid statements include: NM is opposite ∠L; ML is opposite ∠N; and LN serves as the hypotenuse (across from the right angle M).
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Billy graphed the system of linear equations to find an approximate solution. y = A system of equations. y equals negative Start
babunello [11817]

Response:

Second option: (2.2, -1.4)

Third option: (2.2, -1.35)

Detailed explanation:

The missing graph has been provided.

The attached image illustrates the graphing of the following system of linear equations:

\left \{ {{y=-\frac{7}{4}x+\frac{5}{2}} \atop {y=\frac{3}{4}x-3}} \right.

Notice the intersection of the lines.

According to the definition, if lines in a system of equations intersect, then there is only one solution. This implies that the intersection point is the solution to that system. This can be expressed as:

(x,y)

Represented by "x" for the x-coordinate and "y" for the y-coordinate.

Here, it's noticeable that:

- The x-coordinate of the intersection point lies between  x=2 and x=3.

- The y-coordinate of the intersection point is situated between  y=-1 and y=-2.

Therefore, you can conclude that the forthcoming points (Refer to the options given in the exercise) are potential approximations for this system:

(2.2, -1.4)\\\\\\(2.2, -1.35)

7 0
3 months ago
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Patricia wishes to have a rectangular-shaped garden in her backyard. she has 82 ft of fencing material with which to enclose her
tester [12383]
width = x perimeter = 80 or 2(x + l) = 80. Therefore, l = length = 40 - x, leading to the area = x(40 - x), which cannot equal zero. Thus, the condition is x(40 - x) > 0, establishing the domain as 0.
7 0
1 month ago
Using the quadratic formula to solve 2x2 = 4x – 7, what are the values of x? 2 plus-or-minus StartRoot 10 EndRoot i 1 plus-or-mi
AnnZ [12381]

Answer:

x = 1 +/- \frac{i\sqrt{10} }{2}

Step-by-step explanation:

The equation provided is:

2x^2 = 4x - 7\\\\2x^2 - 4x + 7 = 0

Applying the quadratic formula:

x = \frac{-b +/- \sqrt{b^2 - 4ac} }{2a}

Based on the details given:

a = 2, b = -4, c = 7

Consequently:

x = \frac{4 +/- \sqrt{(-4)^2 - 4 * 2 * 7} }{2 * 2}\\\\x = \frac{4 +/- \sqrt{(16 - 56)} }{4}\\\\x = \frac{4 +/- \sqrt{-40} }{4}\\

=> x = 1 +/- \frac{i\sqrt{10} }{2}

7 0
2 months ago
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