Sara is writing a program to input her monthly phone bills and output the month name and amount for the month with maximum amoun

Answer:

In C++:

#include <iostream>

#include <string>

#include <sstream>

using namespace std;

int main(){

   string lname, fname, stringnum;    int num; string login, pwd;

   cout<<"Last Name: ";    cin>>lname;

   cout<<"First Name: ";    cin>>fname;

   cout<<"Four-digit integer: ";    cin>>num;

   stringnum = to_string(num).substr(0, 4);

   stringstream geek(stringnum);    geek>>num;

   num = num%100;

   pwd = to_string(num);

   if(lname.length()<5){ login = lname + fname.substr(0, 1);    }

   else{ login = lname.substr(0, 5) + fname.substr(0, 1);    }

   cout<<"Login Name: "<<login<<endl;

   cout<<"Password: "<<pwd<<endl;

   return 0;

}

Explanation:

This initializes all the required variables

   string lname, fname, stringnum;    int num;     string login, pwd;

This asks the user for their last name

   cout<<"Last Name: ";    cin>>lname;

This asks for the first name of the user

   cout<<"First Name: ";    cin>>fname;

This prompts for a four-digit number

   cout<<"Four-digit integer: ";    cin>>num;

This converts the number into a string and extracts the first four digits

   stringnum = to_string(num).substr(0, 4);

This changes the string back into an integer

   stringstream geek(stringnum);    geek>>num;

This extracts the last two digits of the four-digit number

   num = num%100;

This generates the user's password

  pwd = to_string(num);

This constructs the user's login name.

This block runs if the last name has fewer than five letters

   if(lname.length()<5){ login = lname + fname.substr(0, 1);    }

This block runs otherwise

   else{ login = lname.substr(0, 5) + fname.substr(0, 1);    }

This displays the login name

   cout<<"Login Name: "<<login<<endl;

This displays the password

   cout<<"Password: "<<pwd<<endl;

Answer:

import random

def name_change( name: list ) -> list :

   choice = random.choice( name )

   choice_index = name.index( choice )

   name.pop( choice_index )

   return name

Explanation:

The provided Python code utilizes the random library to randomly select an item from a list within the function "name_change". The index of the selected item is then retrieved from the list and removed from the original list called "name", with the modified name subsequently returned.

To activate the function, assign it to a variable, supply a list (it must be a list) as its argument, and then express the result.

Answer:

a) Transforming each character into its binary equivalent:

73:

The digits are 7 and 3

7 in binary is: 111

3 in binary is: 11

Thus

73: 0_111_0011

Likewise

F4:

F stands for 15 and its binary is: 1111

4 in binary: 100

Consequently

F4:  1_111_0100

E5:

E corresponds to 14 and its binary form is: 1110

5 in binary: 101

Therefore

E5:  1_110_0101

76:

7 in binary: 111

6 in binary: 110

Hence

76:  0_111_0110

E5:

E has a binary representation of: 1110

5 in binary: 101

Consequently

E5:  1_110_0101

4A:

4 in binary: 100

A represents 10

A in binary form: 1010

Therefore

4A:  0_100_1010

EF:

E in binary is: 1110

F in binary is: 1111

Thus

EF: 1_110_1111

62:

6 in binary form: 110

2 in binary form: 10

Therefore

62:  0_110_0010

73:

The digits are 7 and 3

7 in binary is: 111

3 in binary is: 11

Thus

73: 0_111_0011

for 0_1110011: the decimal equivalent is: 115 which translates to s

for 1_1110100:  the decimal equivalent is: 116 which translates to t

for 1_1100101:  the decimal equivalent is: 101 which translates to e

for 0_1110110: the decimal equivalent is:  118 which translates to v

for 1_1100101:  the decimal equivalent is: 101 which translates to e

for 0_1001010: the decimal equivalent is:  74 which translates to j

for 1_1101111: the decimal equivalent is: 111 which translates to o

for 0_1100010:  the decimal equivalent is: 98 which translates to b

for 0_1110011: the decimal equivalent is:  115 which translates to s

Thus the decoded sequence is:  stevejobs

b) The parity being utilized is odd.

for 0_1110011:  There are 5 instances of 1s and the parity is 0 indicating it is odd.

for 1_1110100: There are 4 instances of 1s and the parity is 1 indicating it is odd.

Thus, we count the number of 1s and then verify if the parity is odd or even.

Likewise

for 1_1100101:  the parity is odd

for 0_1110110: the parity is odd

for 1_1100101:  the parity is odd

for 0_1001010: the parity is odd

for 1_1101111: the parity is odd

for 0_1100010: the parity is odd

for 0_1110011: the parity is odd

Therefore, the parity being used is odd.