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stich3
2 months ago
7

Convert Newton’s method for approximating square roots in Project 1 to a recursive function named newton. (Hint: The estimate of

the square root should be passed as a second argument to the function.) An example of the program
Computers and Technology
1 answer:
Amiraneli [1K]2 months ago
3 0
The code provided implements Newton's method for estimating square roots as a recursive function named 'newton'. The calculations to determine the approximation for the square root and the differences are handled within the function. If the difference is below the set tolerance, the approximation is returned; otherwise, the function recursively calls itself with the updated approximation.
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Joe mama is the most extraordinary person on the planet.
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2 months ago
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Given: an int variable k, an int array current Members that has been declared and initialized, an int variable memberID that has
Natasha_Volkova [1026]

Answer:

The following C++ program is displayed below. No output is produced as per the requirements stated in the question.

#include <iostream>

using namespace std;

int main() {    

   // declaration and initialization of integer variables

   int k, memberID = 12, nMembers=5;

   bool isAMember;    

   // declaration and initialization of integer array

   int currentMembers[] = {12, 34, 56, 78, 90};    

   for(k=0; k<nMembers; k++)

   {

       if(memberID == currentMembers[k])

       {

           // if the member is found in the array, the loop exits using the break statement

           isAMember = true;

           break;

       }

       else

           isAMember = false;

   }    

   return 0;

}

Explanation:

The program starts with the declaration and initialization of integer variables, followed by the definition of an array that holds the identifiers of all members.

The Boolean variable is declared, although it isn't initialized at this point.

int k, memberID = 12, nMembers=5;

bool isAMember;

int currentMembers[] = {12, 34, 56, 78, 90};

Subsequently, the array containing the members' IDs is searched for the specific member ID. This action is performed using a for loop along with an if-else condition within that loop.

If the member ID exists in the array, the variable isAMember is set to true; otherwise, it is marked as false.

If isAMember is set to true, the break statement allows for the loop to be exited early.

for(k=0; k<nMembers; k++)

   {

       if(memberID == currentMembers[k])

       {

           isAMember = true;

           break;

       }

       else

           isAMember = false;

 }

The break statement is utilized since any other IDs in the array won't match the given member ID and thus, the variable isAMember would incorrectly be initialized to false even if the member ID is present in the array. Therefore, it's crucial to terminate the loop as soon as the matching member ID is located.

This program can be tested by utilizing different member ID values and varying the size of the array.

4 0
1 month ago
Create an algorithm that will convert dog years to human years using the assumption that 1 dog year = 7 human years. Prompt the
amid [951]

Response:

Procedure:

1. Define and set the variable one_dog_year to 7.

2.Request the user to input the dog's age.

   2.1 Capture the entered dog age and store it in variable "dog_age".

3.Generate a variable "human_age" for the corresponding human age.

   3.1 Compute the equivalent human age using the formula "human_age=one_dog_year*dog_age".

4.Display the calculated human age that corresponds to the dog's age.

7. Conclude the program.

// following is the algorithm executed in c++

#include <bits/stdc++.h>

using namespace std;

int main()

{

   // set one dog year

   int one_dog_year=7;

   int dog_age;

   int equi_h_age;

   cout<<"Enter the dog age:";

   // get the dog age

   cin>>dog_age;

   

   //determine the corresponding human age

   equi_h_age=dog_age*one_dog_year;

   cout<<"equivalent human age is: "<<equi_h_age<<endl;

return 0;

}

Result:

Enter the dog age:2

equivalent human age is: 14

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1 month ago
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