Answer:
(C) 10% to 70%(
Step-by-step explanation:
Given that at least 40% of the students are learning German, the upper limit of those who might be enrolled in English but not in German is 60%. However, since a minimum of 70% study English, it leads to the conclusion that at least 10% of students must be taking both German and English.
If we consider that at least 30% of students are learning Italian, and assuming that no student is studying all three languages simultaneously, then there is a maximum of 70% of students who could potentially be registered in both English and German.
This means the possible percentage for students enrolled in both English and German ranges from 10% to 70%
X^2 - x - 90 =0
This quadratic equation is in the standard format ax^2+ bx + c
The total of the solutions can be found using -b/a (where a and b are the coefficients from the original equation, not the solutions)
The resulting answer is 1/1 = 1
Let's start by calculating the cost of the first 10 boxes, which totals $75, and the next 10 boxes cost $55.
Together, these 20 boxes amount to $130 spent. With $18 remaining, you can purchase 4 more boxes since 18 divided by 4.5 equals 4.
Therefore, the maximum number of boxes you can buy with $148 is 24.
Response:
The problem is summarized in the following explanation segment.
Detailed explanation:
The estimate of the slots or positions lost due to simultaneous transmission attempts can be calculated as follows:
Evaluating the likelihood of transmitting gives us "p".
When considering two or more attempts, we arrive at
Fraction of slots wasted,
= ![[1-no \ attempt \ probability-first \ attempt \ probability-second \ attempt \ probability+...]](https://tex.z-dn.net/?f=%5B1-no%20%5C%20attempt%20%5C%20probability-first%20%5C%20attempt%20%5C%20probability-second%20%5C%20attempt%20%5C%20probability%2B...%5D)
Substituting the values yields
= ![1-no \ attempt \ probability-[N\times P\times probability \ of \ attempts]](https://tex.z-dn.net/?f=1-no%20%5C%20attempt%20%5C%20probability-%5BN%5Ctimes%20P%5Ctimes%20probability%20%5C%20of%20%5C%20attempts%5D)
= ![1-(1-P)^{N}-N[P(1-P)^{N}]](https://tex.z-dn.net/?f=1-%281-P%29%5E%7BN%7D-N%5BP%281-P%29%5E%7BN%7D%5D)
Thus, the answer appears to be correct.
Answer:
0.93 minute
Step-by-step explanation:
During the first week:
Kim ran = 1 mile
Duration for this distance = 1 minute
In the second week:
The distance covered by Kim = 1 mile
The time taken by Kim = 7% less compared to the first week
= 1 min - 0.07 min = 0.93 minute
<pSo, she completed 1 mile in 0.93 minute this week.
