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rewona
2 months ago
9

Todd had 6 gallons of gasoline in his motorbike. After driving 150​ miles, he had 3 gallons left. Compute the​ slope, or rate of

change in the amount of gasoline.
Mathematics
2 answers:
Svet_ta [12.7K]2 months ago
8 0
He can drive 50 miles for every gallon of gas used. Therefore, I believe the slope to be 50/-1
AnnZ [12.3K]2 months ago
8 0

Answer:

Given,

Todd started with 6 gallons of gasoline in his motorbike. After traveling 150 miles, he had 3 gallons remaining.

When Todd had 6 gallons, he hadn't traveled any distance,

and when he had 3 gallons left, he had covered 150 miles.

Thus, the slope or rate of change = \frac{3-6}{150-0} =\frac{-3}{150} =-\frac{1}{50} = - 0.02

Indicating that the slope or rate of change in gasoline is negative, signifying a decrease in fuel as miles increase.

The slope or rate of change of gasoline= - 0.02 gallons/mile


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Marlo uses 252 lb of gravel to cover a garden plot of 36 ft2. How many pounds of gravel does it take to cover one square foot? H
babunello [11817]

The amount of gravel and the area it covers are examples of ratios.

A weight of 7 lb can cover 1 square foot, while 315 lb can cover an area of 45 square feet.

The relevant parameters are:

252\ lb= 36ft^2

To find the number of pounds needed for 1 square foot , perform the following calculation:

x = 1ft^2

Thus, we have:

x = 1ft^2

252\ lb= 36ft^2

Cross multiply

x \times 36 = 252 \times 1

And divide both sides by 36

x = 7lb

The area that 315 lb of gravel can cover is calculated as follows:

So, we have:

315lb = y

315lb = y

Cross multiply

252\ lb= 36ft^2

y \times 252 = 36 \times 315

And divide both sides by 252

y \times 252 = 11340

Thus, 7 lb will cover

1 square footy = 45, and 315 lb will encompass an area of

45 square feet.

Read more about ratios at:

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Suppose you earn $5.50 an hour working at the plant nursery on weekends. Given your table of values in part a, write an equation
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Answer:

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Step-by-step explanation:

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Answer:

Indeed, the equation is solvable by factoring. By applying the given equation, you can take the square root of both sides. Since both 169 and 9 are perfect squares, the left-hand side simplifies to plus or minus 13/3, producing rational results. Adding 6 to 13/3 yields a rational number while subtracting it does too. Thus, a quadratic equation is factorable if its solutions are rational.

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