Answer:
The standard ticket price was $12.
Step-by-step explanation:
Let’s denote 
the normal ticket price, which would total
if she had purchased tickets for that amount.
However, since Holly received a $4 discount on each ticket, her cost for one ticket became
and with 23 tickets, her total cost was
amounting to $184; thus, we conclude
we will solve this equation as follows:
Therefore, the regular price amounted to $12.
Let L represent the yards in a roll of lace ribbon and S represent the yards in a roll of satin ribbon. We can formulate two equations: 3L + 2S = 120 yards (Equation 1) and 2L + 4S = 160 yards (Equation 2). If we multiply Equation 1 by 2 and subtract Equation 2, we have: 6L + 4S = 240 yards (Equation 1) and 2L + 4S = 160 yards (Equation 2). Thus, 4L equals 80 yards, leading to L equating to 20 yards. For Equation 1, substituting gives 3(20 yards) + 2S = 120 yards, leading to 2S equal to 60 yards, so S equals 30 yards. Therefore, a roll of lace ribbon contains 20 yards, while a roll of satin ribbon has 30 yards.
The formula for distance in this scenario is:
d ^ 2 = (12 * 1.5) ^ 2 + (8 * 1.5) ^ 2
Rewriting gives us:
d ^ 2 = (18) ^ 2 + (12) ^ 2
d ^ 2 = 324 + 144
d ^ 2 = 468
d = √(468)
d = 21.63 Km
Answer:
1) She failed to calculate the total distance each had covered in 1.5 hours.
2) She should have applied 12 km for Joseph's distance and 18 km for Isabelle's distance.
Response:
After 15 years, the balance in the account should be $95,321.85
Detailed explanation:
Based on the provided information, we can summarize as follows:
monthly deposit of $220=R
annual interest rate is set at 2.05%. To find the monthly interest rate, we divide: monthly interest rate= 2.05%/12=0.1708%=0.0017
t=15years×12=180 months
To determine the total amount after 15 years, we can apply this formula:
Ap=R(1-(1+i)∧-t)
i
Ap=220(1-(1+0.0017)∧-180)
0.0017
Ap=162,04
0.0017
Ap=$95,321.85
The balance in the account after 15 years is $95,321.85
