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MrRa
3 months ago
9

Zoe draws ΔABC on the coordinate plane. What is the approximate perimeter of ΔABC

Mathematics
2 answers:
zzz [12.3K]3 months ago
6 0

Answer:

Correct answer is Option C.

Step-by-step explanation:

Provided: Triangle ABC plotted on the coordinate plane.

The coordinates given are A( 1, 1 ), B( 3, 5 ), and C( 5, 1 ).

We need to determine the approximate perimeter of the triangle.

We will utilize the distance formula for two points (x_1,y_1)\:and\:(x_2,y_2)

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Thus,

AB=\sqrt{(3-1)^2+(5-1)^2}=\sqrt{(2)^2+(4)^2}=\sqrt{4+16}=\sqrt{20}=4.47\:(approx.)

CB=\sqrt{(5-3)^2+(1-5)^2}=\sqrt{(2)^2+(-4)^2}=\sqrt{4+16}=\sqrt{20}=4.47\:(approx.)

AC=\sqrt{(5-1)^2+(1-1)^2}=\sqrt{(4)^2+(0)^2}=\sqrt{16}=4

Therefore, the Perimeter = AB + AC + CB = 4.47 + 4.47 + 4 = 12.94 units

Consequently, Option C is correct.

lawyer [12.5K]3 months ago
5 0
B. 12 units because the total length calculated together results in 12.
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Answer:

The correct statements are options 1 (E F + F G > E G), 2 (E G + F G > E F), and 5 (E G + E F < F G).

Step-by-step explanation:

We have triangle EFG.

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Specifically for triangle EFG:

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