What is the surface area of the regular pyramid below

Answer:

The universal formula applicable for determining the necessary combinations of n ice cream flavors.

For 10 flavors of ice cream

Step-by-step explanation:

Let's denote V = Vanilla, C = Chocolate, S = Strawberry, P = Pineapple, B = Berry

For 2 flavors of ice cream:

V, C

{V/V, V/C, C/C}

3 possible combinations

For 3 flavors of ice cream:

V, C, S

{V/V, V/C, V/S, C/S, C/C, S/S}

6 possible combinations

For 4 flavors of ice cream:

V, C, S, P

{V/V, V/C, V/S, V/P, C/S, C/P, S/P, C/C, S/S, P/P}

10 possible combinations

For 5 flavors of ice cream:

V, C, S, P, B

{V/V, V/C, V/S, V/P, V/B, C/S, C/P, C/B, S/P, S/B, P/B, C/C, S/S, P/P, B/B }

15 possible combinations

Thus, we derive a sequence of

3, 6, 10, 15...

This sequence is recognized as the Triangular number series

1 + 2 = 3

1 + 2 + 3 = 6

1 + 2 + 3 + 4 = 10

1 + 2 + 3 + 4 + 5 = 15

The general formula for this sequence is

Utilizing this formula allows us to predict the number of 2-scoop combinations from 10 flavors.

Consequently, there are 55 varying combinations for a 2-scoop cone when selecting from 10 flavors.

His annual savings over 52 weeks amounts to $867.

Answer:

B

Step-by-step explanation:

If two quantities have a direct variation, their graph will originate from the point of intersection at the origin.

Among all graphs, only Nikiya's intersects the origin, thus the answer is B.

(a) The likelihood that all 5 eggs chosen are unspoiled is 0.0531. (b) The probability that 2 or fewer out of the 5 eggs are unspoiled is 0.3959. (c) The probability that more than 1 of the selected 5 eggs are unspoiled is 0.8747. Step-by-step explanation: The complete query is: A subpar carton of 18 eggs has 8 that are spoiled. An unsuspecting chef selects 5 eggs at random for his “Mega-Omelet Surprise.” Calculate the probability of receiving (a) exactly 5 unspoiled eggs, (b) 2 or fewer, and (c) more than 1 unspoiled egg. Define X = number of unspoiled eggs. In the faulty carton, 8 eggs are spoiled. The probability of selecting an unspoiled egg is independent of others. Provided that a chef randomly picks 5 eggs, the variable X follows a Binomial distribution with parameters n = 5 and p = 0.556. Success is defined as selecting an unspoiled egg. The probability mass function of X is as follows: (a) Calculate the probability of selecting all unspoiled eggs. Thus, this probability is found to be 0.0531. (b) For 2 or less unspoiled eggs, the probability is computed: P (X ≤ 2) = P (X = 0) + P (X = 1) + P (X = 2), resulting in a probability of 0.3959. (c) For more than 1 unspoiled egg: P (X > 1) = 1 - P (X ≤ 1), yields a final probability of 0.8747.

Answer: 0.31

Step-by-step explanation:

Let A signifies the event of the Tampa Bay Buccaneers scoring a touchdown on their initial drive while B signifies the occurrence of their defense achieving 3 or more sacks during the game.

Given: P(A)=0.14     P(B) = 0.31     P(A or B)=0.14

Formula: P(A and B)= P(A) + P(B) - P(A or B)

Now, we calculate the probability of both scoring a touchdown on the initial drive and achieving 3 or more sacks in the game as follows:-

P(A and B)= 0.14 + 0.31 - 0.14=0.31

Therefore, the required probability is: 0.31