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Alex73
12 days ago
15

Point of tangency of an inscribed circle divides a leg of an isosceles triangle into 3 cm and 4 cm line segments (considered fro

m the vertex to the base). Find the perimeter of the triangle.
Mathematics
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Which graph represents a reflection of f(x) = 6(0.5)x across the x-axis?
Inessa [12570]
The blue line depicted in the attached image illustrates the reflection of f(x) across the x-axis. To elucidate, the function f(x) is an exponential function displaying the characteristics: the y-intercept calculates as f(0) = 6(0.5)⁰ = 6; the multiplicative rate of change is 0.5, signifying a decay function (decreasing); and the horizontal asymptote exists at y = 0, defining the limit of f(x) as x approaches positive infinity. The reflection across the x-axis for f(x) results in a function denoted as g(x) = -f(x), leading to g(x) reflecting the features discussed including growth into the third quadrant while never intersecting the x-axis. Therefore, using these insights, it is feasible to sketch the corresponding graph across the x-axis.
5 0
1 month ago
Read 2 more answers
100 point!!!
Leona [12618]

Answer:

45 grams

Step-by-step explanation:

1st order: 27 people

15 people:

100 g

Ginger: 20 g

Turmeric: 25 g

Coriander: 35 g

Cumin Seeds: 20 g

20+25+35+20=60+40=100

For 1 person:

Ginger: 1 1/3 g

Turmeric: 1 2/3 g

Coriander: 2 1/3 g

Cumin Seeds: 1 1/3 g

Multiply the total by 27

For 27 people:

Ginger: 36 g

Turmeric: 45 g

Coriander: 63 g

Cumin Seeds: 36 g

45 g for Turmeric

4 0
1 month ago
Sin 1 + sin 2 + sin3 .................+ sin 360 = ?
PIT_PIT [12445]

Assuming arcs are measured in degrees, let S represent the following sum:

S = sin 1° + sin 2° + sin 3° +... + sin 359° + sin 360°


By rearranging, S can be reformulated as

S = [sin 1° + sin 359°] + [sin 2° + sin 358°] +... + [sin 179° + sin 181°] + sin 180° +
+ sin 360°

S = [sin 1° + sin(360° – 1°)] + [sin 2° + sin(360° – 2°)] +... + [sin 179° + sin(360° – 179)°]
+ sin 180° + sin 360°          (i)


However, for any real k,

sin(360° – k) = – sin k


Thus,

S = [sin 1° – sin 1°] + [sin 2° – sin 2°] +... + [sin 179° – sin 179°] + sin 180° + sin 360°

S results in 0 + 0 +... + 0 + 0 + 0        (... since sine of 180° and 360° are both equal to 0)

Therefore, S equals 0.


Each pair within the brackets negates itself, leading the sum to total zero.

∴   sin 1° + sin 2° + sin 3° +... + sin 359° + sin 360° equals 0.          ✔


I hope this clarifies things. =)


Tags:  sum summatory trigonometric trig function sine sin trigonometry

4 0
2 months ago
Help me please,Thanks
tester [12383]
The solution is 24m^2; I just completed that test and that was the result.<span />
4 0
1 month ago
Segment JK has a length of 4.5 units. If segment LM has end points of L (3,1) and M (-1,4), how much longer than segment JK is s
Leona [12618]
Distance formula:
d= \sqrt{ (x_{2}-x_{1}) ^{2}+( y_{2} - y_{1} )^{2}}\\ d= \sqrt{ (3-(-1)) ^{2}+(1 - 4 )^{2}}\\ d= \sqrt{ (4) ^{2}+(-3)^{2}}\\ d=\sqrt{16+9}\\ d=\sqrt{25}\\ d=5

5 units-4.5 units=0.5 units

Segment LM exceeds segment JK by 0.5 units.
4 0
2 months ago
Read 2 more answers
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