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Alecsey
2 months ago
14

Anumeha is mowing lawns for a summer job. For every mowing job, she charges an initial fee of $ 10 $10dollar sign, 10 plus a con

stant fee for each hour of work. Her fee for a 5 55-hour job, for instance, is $ 35
Mathematics
1 answer:
Zina [12.3K]2 months ago
6 0

Answer:

F(t) = 10 + 5(t)

Step-by-step explanation:

The complete question is as follows;

Anumeha is mowing lawns for a summer job. For each lawn she mows, she charges a $10 starting fee plus an hourly rate. For example, her fee for a 5-hour job is $35. Let f(t) denote Anumeha's fee for a job f (in dollars) based on how many hours (t) were needed to finish it. Write the formula for this function.

Solution

We aim to establish the formula F(t) representing the fee Anumeha charges per job.

Key to formulating this function is understanding the constant charge she applies per job.

We know she earns $35 for mowing for 5 hours.

Therefore, the constant fee can be deduced as follows;

Since it’s a $10 starting fee along with an hourly rate;

35 = 10 + 5(x)

where x refers to the hourly rate

35 = 10 + 5x

5x = 35-10

5x = 25

x = 25/5

x = $5

This indicates that she charges a constant fee of $5 per hour

Thus, we can now write the equation.

F(t) = 10 + 5(t)

where t represents the number of hours spent on each job

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A function f(x) has x intercepts of -3 and -5. What is the constant term in the function?
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Match each pair of points to the equation of the line that is parallel to the line passing through the points.
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It's known that

When two lines are parallel, their slopes are identical.

The slope between any two points can be calculated using the following formula:


m=\frac{y2-y1}{x2-x1}


We will calculate the slope for each case to find the solution to the problem.

Case A) Point B(5,2)\ C(7,-5)

Determine the slope of BC

Insert the values into the formula:

m=\frac{-5-2}{7-5}


m=\frac{-7}{2}


m=-3.5


Thus,

The equation y=-3.5x-15 is parallel to the line that goes through the points B(5,2)\ C(7,-5)

Therefore,

the result for Part A) is

B(5,2)\ C(7,-5) ------> y=-3.5x-15

Case B) Point D(11,6)\ E(5,9)

Calculate the slope of DE

Plug the values into the formula:

m=\frac{9-6}{5-11}


m=\frac{3}{-6}


m=-0.5


Thus,

The equation y=-0.5x-3 is parallel to the line that goes through the points D(11,6)\ E(5,9)

Therefore,

the result for Part B) is

D(11,6)\ E(5,9) ------> y=-0.5x-3

Case C) Point F(-7,12)\ G(3,-8)

Determine the slope of FG

Insert the values into the formula:

m=\frac{-8-12}{3+7}

m=\frac{-20}{10}


m=-2


Thus,

Any linear equation with slope m=-2 will be parallel to the line through the points F(-7,12)\ G(3,-8)

Case D) Point H(4,4)\ I(8,9)

Calculate the slope of HI

Substitute the values in the formula:

m=\frac{9-4}{8-4}


m=\frac{5}{4}


m=1.25


Thus,

The equation y=1.25x+4 is parallel to the line through the points H(4,4)\ I(8,9)

Therefore,

the result for Part D) is

H(4,4)\ I(8,9) ------> y=1.25x+4

Case E) Point J(7,2)\ K(-9,8)

Determine the slope of JK

Insert the values into the formula:

m=\frac{8-2}{-9-7}


m=\frac{6}{-16}


m=-0.375


Thus,

Any linear equation characterized by slope m=-0.375 will be parallel to the line that runs through the points J(7,2)\ K(-9,8)

Case F) Point L(5,-7)\ M(4,-12)

Find the slope of LM

Substitute the values in the formula:

m=\frac{-12+7}{4-5}


m=\frac{-5}{-1}


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Thus,

The equation y=5x+19 is parallel to the line connecting the points L(5,-7)\ M(4,-12)

Therefore,

the result for Part F) is

L(5,-7)\ M(4,-12) ------> y=5x+19




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