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2 months ago

Find the amount of elapsed time between each pair.

2 answers:

8 0

A) 2 hours 45 minutes
b) 7 hours 34 minutes
c) 6 hours 14 minutes
d) 7 hours 55 minutes
e) 10 hours 59 minutes
f) 8 hours 59 minutes

tester [12.3K]2 months ago

5 0

Response:

Detailed explanation:

To determine the elapsed time between each pair, we perform subtraction.

A. From 8:30 am to 11:15 am = 11:15 - 8:30 = 2 hours 45 minutes

B. When one time is in the a.m. and the other is in the p.m., convert the p.m. time to the 24-hour format; for instance, 4:44 pm becomes 16:44 pm. This makes subtraction straightforward.

B. From 9:10 am to 4:44 pm = 16:44 - 9:10 = 7 hours 34 minutes

C. From 5:15 pm to 11:29 pm = 11:29 - 5:15 = 6 hours 14 minutes

D. From 5:20 p.m. to 1:15 am = 17:20 - 1:15 = 7 hours 55 minutes

E. From 8:36 am to 7:35 pm = 19:35 - 8:36 = 10 hours 59 minutes

F. From 3:00 pm to 11:59 pm = 15:00 - 11:59 = 8 hours 59 minutes.

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Which property does each equation demonstrate? x2 + 2x = 2x + x2 (3z4 + 2z3) – (2z4 + z3) = z4 + z3 (2x2 + 7x) + (2y2 + 6y) = (2

babunello [11817]

Response:

1. Closure

2. Distributive

3. Closure

Detailed explanation:

In this scenario, we are examining the properties that each equation demonstrates.

The first equation shows the closure property.

This indicates that whether we add in one direction or the other, the result remains unchanged. Therefore, we conclude that addition conforms to the closure property in this case.

The third equation also shows the closure property. Regardless of how we approach the addition for this equation, the outcome remains consistent.

The second equation displays the distributive property.

Each element within the parentheses is multiplied by the negative sign before we proceed with further calculations.

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3 months ago

Jenny multiplies the square root of her favorite positive integer by $\sqrt{2}$. Her product is an integer. a) Name three number

tester [12383]

Answer:Part a) $2,50,18$

Part b) When Jenny divides the square root of her favorite positive integer by $\sqrt{2}$ , the result is an integer.

Step-by-step explanation:

Let

x-------> the favorite positive integer

Part a)

1) For $x=2$

$\sqrt{2}*\sqrt{2}=\sqrt{4}=2$ -----> the product results in an integer

thus

The number $x=2$ could potentially be Jenny's favorite positive integer

2) For $x=50$

$\sqrt{50}*\sqrt{2}=\sqrt{100}=10$ -----> the product results in an integer

thus

The number $x=50$ could potentially be Jenny's favorite positive integer

3) For $x=18$

$\sqrt{18}*\sqrt{2}=\sqrt{36}=6$ -----> the product results in an integer

thus

The number $x=18$ could potentially be Jenny's favorite positive integer

Part B)

1) For $x=2$

$\sqrt{2}/\sqrt{2}=\sqrt{1}=1$ -----> the outcome is an integer

2) For $x=50$

$\sqrt{50}/\sqrt{2}=\sqrt{25}=5$ -----> the outcome is an integer

3) For $x=18$

$\sqrt{18}/\sqrt{2}=\sqrt{9}=3$ -----> the outcome is an integer

Therefore

When Jenny divides the square root of her favorite positive integer by $\sqrt{2}$ , she obtains an integer as a result.

4 0

2 months ago

If 30,000 cm2 of material is available to make a box with a square base and an open top, what is the largest possible volume (in

Inessa [12570]

Answer:

The highest achievable volume for the box is 2000000 cubic meters.

Step-by-step explanation:

Below is an outline of the volume ( $V$ ), measured in cubic centimeters, and surface area ( $A_{s}$ ), measured in square centimeters, for a box featuring a square base:

$A_{s} = l^{2}+h\cdot l$ (1)

$V = l^{2}\cdot h$ (2)

Where:

$l$ - The length of the base's side, in centimeters.

$h$ - The height of the box, in centimeters.

Using (2), we isolate $h$ in the formula:

$h = \frac{V}{l^{2}}$

Then, we substitute into (1) and simplify the outcome:

$A_{s} = l^{2}+ \frac{V}{l}$

$A_{s}\cdot l = l^{3}+V$

$V = A_{s}\cdot l -l^{3}$ (3)

Next, we calculate the first and second derivatives of this expression:

$V' = A_{s}-3\cdot l^{2}$ (4)

$V'' = -6\cdot l$ (5)

If $V' = 0$ and $A_{s} = 30000\,cm^{2}$ , then we find that the critical value for the base's side length is:

$30000-3\cdot l^{2} = 0$

$3\cdot l^{2} = 30000$

$l = 100\,cm$

Subsequently, we assess this outcome using the second derivative's expression:

$V'' = -600$

According to Second Derivative Test, this critical value signifies an absolute maximum. Consequently, the largest volume obtainable for the box is:

$V = 30000\cdot l - l^{3}$

$V = 2000000\,cm^{3}$

The highest achievable volume for the box is 2000000 cubic meters.

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2 months ago

Jamal is comparing his transportation options for an upcoming trip. He’s considering a rental car and a taxi service. Based on h

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2 months ago