5(11 squared + 1) plus 16
5(121 + 1) plus 16
5(122) plus 16
605 plus 16
p(11) equals 626
The answer must be B Step-by-step explanation:
Answer: 8x - 1200
Step-by-step explanation: I solved the problem
Given:
Two identical parallelograms total area = 9 1/3 yd²
Each parallelogram has height 1 1/3 yd
Area formula: area = base × height
Split the total area equally to find each parallelogram's area.
Convert 9 1/3: (9*3)+1 = 28/3
Divide by 2: 28/3 × 1/2 = 28/6 yd², which is 4 4/6 yd² → 4 2/3 yd²
So each parallelogram's area is 4 2/3 yd²
Set up base × 1 1/3 yd = 4 2/3 yd²
Convert and divide: 14/3 yd² ÷ 4/3 yd = base
Multiply: 14/3 × 3/4 = base
Compute: 14*3 / 3*4 = base
42 / 12 = base
Which simplifies to 3 6/12 yd = base
or 3 1/2 yd = base
a) Each parallelogram has a base of 3 1/2 yards
b) If the two parallelograms form a rectangle:
Rectangle area = length × width
Length = 3 1/2 yd × 2 = 7 yds
Width = 3 1/2 yds
Area = 7 yd × 3 1/2 yd
Area = 7 × 7/2 yd²
Area = 7*7 / 2 yd²
Area = 49 / 2 yd²
Area = 24 1/2 yd²
Response:
Maureen's null hypothesis is, H₀: p₁ ≥ p₂.
Detailed explanation:
Maureen McIlvoy, as the owner and CEO of a mail-order business specializing in windsurfing gear, is scrutinizing the order fulfillment processes in her warehouses. Her objective is to achieve a 100% shipment rate of orders within 24 hours. Upon examining her warehouse operations, she discovers that both the East coast and West coast warehouses have not met this goal, although the East Coast warehouse has consistently outperformed its counterpart.
To verify this finding, Maureen’s team randomly sampled 200 orders from the West Coast warehouse (population 1) and 400 from the East Coast warehouse (population 2).
Of the sampled 200 orders from the West Coast warehouse, 190 were delivered within the specified time. In contrast, 372 out of 400 orders from the East Coast warehouse were processed within 24 hours.
The hypotheses can be formulated as followed:
H₀: The proportion of timely shipments from the East Coast does not exceed that from the West Coast warehouse, thus, p₁ ≥ p₂.
Hₐ: The proportion of timely shipments from the East Coast warehouse is indeed greater than that from the West Coast warehouse, stated as p₁ < p₂.
Thus, Maureen's null hypothesis becomes, H₀: p₁ ≥ p₂.
