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Whitepunk
1 month ago
11

The lengths of a particular snake are approximately normally distributed with a given mean Mu = 15 in. and standard deviation Si

gma = 0.8 in. What percentage of the snakes are longer than 16.6 in.? 0.3% 2.5% 3.5% 5%
Mathematics
2 answers:
AnnZ [12.3K]1 month ago
7 0

Response: 5%

Detailed explanation:

Consider snakes exceeding 16.6 inches in length. This length is above the average by 1.6 inches, as mean length is 15 inches.

1.6:Sigma=1.6: 0.8=2 indicates that snakes longer than 16.6 inches fall within the two standard deviations. It’s established that roughly 95.4% of snakes follow a normal distribution within two standard deviations

Thus, there would be 100%-95.4%=4.6%, which is approximately 5%, of snakes measuring over 16.6 inches

babunello [11.8K]1 month ago
3 0

Response:

D

Detailed explanation:

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Serena estimates that she can paint 60 square feet of wall space every half -hour .Write a equations for the relationship with t
Inessa [12570]

Response: Therefore, the connection with i hours being the independent variable is y=120i

Serena is unable to paint 400 square feet of wall area within 3.5 hours.

Detailed explanation:

It's provided that

The area she can paint = 60 square feet

Time taken = half an hour = 30 minutes = 0.5 hours

Applying the "Unitary method, it leads to

In 0.5 hours, she is capable of painting = 60 square feet

In 1 hour, she can paint = \dfrac{60}{0.5}=120\ sq.\ feet

In i hours, she is able to paint = 120\times i\ sq.\ feet=120i\ sq.\ feet

Let’s denote the total area she can paint as 'y'.

Thus, the connection with i hours treated as the independent variable would be

y=120i

Now,  Can Serena paint 400 square feet of wall area in 3.5 hours

Substituting y = 400 and i = 3.5 hours helps us determine if they are equivalent.

400= 120\times 3.5\\\\400\neq 420

Therefore, Serena cannot paint 400 square feet of wall space in 3.5 hours.

3 0
1 month ago
Triangles A B C and T P Q are shown. Sides A C and T Q are congruent. Angles B C A and P Q T are congruent. Which statements are
PIT_PIT [12445]

Answer:

Triangles would be congruent through ASA if Angle A is equal to Angle T.

Triangles would be congruent via AAS if Angle B matches Angle P.

Step-by-step explanation:

It is established that sides AC and TQ are congruent, along with angles BCA and PQT. If angles A and T are equal, we apply the ASA theorem. Similarly, if angle B equals angle P, we reference the AAS theorem.

Since only two options need to be selected, you can conclude your options there.

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2 months ago
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$0.60 bottle of iced tea marked up to $1.35
zzz [12365]
The result is 0.81 because you must multiply 0.60 by 1.35 to get 0.81. Then divide 0.81 by 0.60.
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2 months ago
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In the figure, CD = EF and AB = CE. Complete the statements to prove that AB = DF.
Svet_ta [12734]

Answer:

1. Addition Property of Equality

2. Segment addition

3. Substitution Property of Equality.

4. Transitive Property of Equality.

Step-by-step explanation:

Given: CD = EF and AB = CE

To Show: AB = DF

Following the steps outlined:

1. CD + DE = EF + DE by the (addition) Property of Equality.

This shows that the same value has been added to both sides of the equation.

2. CE = CD + DE and DF = EF + DE through (segment addition).

This indicates that CE and DF are segments, and the length of any segment equals the total of its parts.

3. CE = DF according to the (Addition, subtraction, substitution, transitive) Property of Equality. Recognizing that CE = CD + DE and using the fact that CD = EF allows us to replace CD with EF.

So, CE = EF + ED = FD (via substitution) Property of Equality.

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This follows the rule that if x = y and y = z, then x = z.

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The table represents the equation y = 2 – 4x. A 2-column table with 5 rows. The first column is labeled x with entries negative
tester [12383]

The missing value associated with x=-1 is y=6

Explanation:

The provided equation for the table is y=2-4x

This table consists of 2 columns and 5 rows.

<pconsequently it="" states="">

x       y

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-1       ---

0        2

1        -2

2       -6

To find the value for y when x=-1

The value of y can be ascertained by substituting x=-1 into the equation y=2-4x

<pthus we="" determine="">

y=2-4(-1)

<pmultiplying the="" term="" within="" brackets="" yields="">

y=2+4

<psumming the="" terms="" we="" find="">

y=6

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</pso></psumming></pmultiplying></pthus></pconsequently>
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