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Whitepunk
2 months ago
11

The lengths of a particular snake are approximately normally distributed with a given mean Mu = 15 in. and standard deviation Si

gma = 0.8 in. What percentage of the snakes are longer than 16.6 in.? 0.3% 2.5% 3.5% 5%
Mathematics
2 answers:
AnnZ [12.3K]2 months ago
7 0

Response: 5%

Detailed explanation:

Consider snakes exceeding 16.6 inches in length. This length is above the average by 1.6 inches, as mean length is 15 inches.

1.6:Sigma=1.6: 0.8=2 indicates that snakes longer than 16.6 inches fall within the two standard deviations. It’s established that roughly 95.4% of snakes follow a normal distribution within two standard deviations

Thus, there would be 100%-95.4%=4.6%, which is approximately 5%, of snakes measuring over 16.6 inches

babunello [11.8K]2 months ago
3 0

Response:

D

Detailed explanation:

You might be interested in
Using a profit P1 of $5,000, a profit P2 of $4,500, and a profit P3 of $4,000, calculate a 95% confidence interval for the mean
PIT_PIT [12445]

Answer:

Confidence Interval

Lower Limit = $4,233.3

Upper Limit = $4,766.7

With 95% certainty, SoftBus can anticipate that the average profit per customer will fall within the range of $4,233.30 to $4,766.7, based on the provided sample data.

Step-by-step explanation:

The z-score corresponding to 95% is 1.96

             Profit         Mean      Square Root

                           Difference    of MD

P1        $5,000       $500        $250,000

P2         4,500          0              0

P3         4,000       -500         $250,000

Total $13,500                        $500,000

Mean $4,500 ($13,500/3)    $166,667 ($500,000/3)

Standard Deviation = Square root of $166,667 = 408.2

Margin of error = (z-score * standard deviation)/n

= (1.96 * 408.2)/3

= 266.7

= $266.7

Confidence Interval = Sample mean +/- Margin of error

= $4,500 +/- 266.7

Lower Limit = $4,233.3 ($4,500 - $266.7)

Upper Limit = $4,766.7 ($4,500 + $266.7)

3 0
1 month ago
At smith mountain lake boat rentals, it costs $25 per hour to rent a pontoon boat, plus a one-time charge for cleaning. The Beng
lawyer [12517]
The equation provided in slope-intercept form is 226.50 = 7.5 (25) + 39. Step-by-step explanation: The slope-intercept form of an equation is represented by y = mx + c. The hourly cost of boat rental is $25. Assuming a one-time cleaning fee of k, and with the boat rented from 11 am to 6:30 pm, the total hours of use amount to 7.5 hours. Consequently, the rental cost for those 7.5 hours becomes 7.5 multiplied by $25, equating to $187.50. The total sum paid by the family amounts to $226.50, which equals the cleaning fee plus the 7.5-hour rate. Thus, the cleaning charge comes to $226.50 - $187.50 = $39. The equation presented reflects this relationship.
8 0
2 months ago
The computers of six faculty members in a certain department are to be replaced. Two of the faculty members have selected laptop
lawyer [12517]

Answer:

a. \frac{1}{15}

b. \frac{2}{5}

c. \frac{14}{15}

d. \frac{8}{15}

Step-by-step explanation:

There are four desktop computers and two laptops.

On a specific day, we will set up 2 of these computers.

To find:

a. What is the probability that both selected computers are laptops?

b. What is the probability that both computers are desktops?

c. What is the probability that at least one computer is a desktop?

d. What is the probability that at least one of each type of computer is included?

Solution:

Using the probability formula for event E:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

a. The number of successful outcomes for both computers being laptops = _2C_2 = 1

Total possible outcomes = 15

The needed probability is \frac{1}{15}.

b. The successful outcomes for both being desktop computers = _4C_2=6

Total possible outcomes = 15

The required probability is \frac{6}{15} = \frac{2}{5}.

c. For at least one desktop:

Two scenarios exist:

1. 1 desktop and 1 laptop:

Successful outcomes = _2C_1\times _4C_1 = 8

2. Both are desktops:

Successful outcomes = _4C_2=6

Total successful outcomes = 8 + 6 = 14

The needed probability is \frac{14}{15}.

d. 1 desktop and 1 laptop:

Successful outcomes = _2C_1\times _4C_1 = 8

Total outcomes = 15

The required probability is \frac{8}{15}.

8 0
2 months ago
Triangle QRS is a right triangle with the right angle at vertex R. The sum of m∠Q and m∠S must be equal to 45°. greater than 45°
AnnZ [12381]

Answer:

     The angles m∠Q and m∠S together equal 90°

Step-by-step explanation:

A right angle measures 90°.

The total measure of angles in a triangle sums to 180°.

This gives us:

m∠Q + m∠S + ∠R = 180°

m∠Q + m∠S + 90° = 180°

Rearranging yields:

m∠Q + m∠S = 180° - 90°

m∠Q + m∠S = 90°

7 0
2 months ago
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