Response:
The outcome is 4144.
Detailed explanation:
We need to determine the peak value of f(x)=
when 
We can represent
as 
Plugging the value of y

= ![3x^{2}(8-x)^{2}[-x+8-x]+3[-x+8-x]](https://tex.z-dn.net/?f=3x%5E%7B2%7D%288-x%29%5E%7B2%7D%5B-x%2B8-x%5D%2B3%5B-x%2B8-x%5D)
= ![3(8-2x)[x^{2}(8-x)^{2}+1]](https://tex.z-dn.net/?f=3%288-2x%29%5Bx%5E%7B2%7D%288-x%29%5E%7B2%7D%2B1%5D)
To find the maximum, we'll set the equation to 0.
Thus, we find:
=> x = 4
And since
> y = 4
Hence, we will substitute these values into the equation to ascertain the maximum value.
= 
= 
= 
=
= 4144
There will still be 34.5 L of water in the two pails combined because no water is lost.
Thus the total remains 34.5 L after transferring water between them.
Let the final amount in the smaller pail be x.
Then the larger pail contains 9x.
So x + 9x = 34.5.
That simplifies to 10x = 34.5.
Dividing both sides by 10 gives x = 3.45.
Therefore the smaller pail held 3.45 L at the end.
Because 0.68 L was poured into it, its initial volume was 2.77 L (3.45 minus 0.68)
We can also deduce the larger pail initially contained 31.73 L
(either 35 minus 2.77, or 9 times 3.45 plus 0.68)
Divide 1006 by 12
1006 / 12 = 83.833
This results in 83 complete trucks
83 * 12 = 996
Hence, 10 cars will be in the final truck
Answer: 0.1289
Step-by-step explanation:
Given: The proportion of students absent on Mondays at a large university.: 
Sample size: 
Mean: 
Standard deviation = 

Let x represent a binomial variable.
Referencing the standard normal distribution table,
(1)
Z score for normal distribution:-

For x=4

For x=3

Thus, from (1)

Consequently, the likelihood of four students being absent = 