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crimeas
2 months ago
11

The volume, in cubic feet, of a right cylindrical silo of height h and radius r is V = πr2h. The height of the silo is h(r) = 3.

5r. Which statements are true regarding the functions described? Check all that apply. To get a volume of 100 cubic feet, the radius must be 2 feet. The domain of V(h(r)) is restricted to values of r greater than 0. The output of V is the input of h. V(h(r)) = 3.5πr3 The volume depends on the radius of the cylinder.

Mathematics
2 answers:
PIT_PIT [12.4K]2 months ago
6 0
- The function V(h(r)) is limited to r values greater than 0. - V(h(r)) = 3.5πr^3. - The volume is affected by the radius of the cylinder.
Inessa [12.5K]2 months ago
3 0
The function V(h(r)) is limited to r values that are greater than 0. V(h(r)) = 3.5πr^3. The volume is dependent on the cylinder's radius. Step-by-step explanation: Edgenuity.
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Maximum value of x3y3 + 3 x*y when x+y = 8.
Inessa [12570]

Response:

The outcome is 4144.

Detailed explanation:

We need to determine the peak value of f(x)= x^{3}y^{3}+3xy when x+y=8

We can represent x+y=8 as y=8-x

Plugging the value of y

f(x)=x^{3}(8-x)^{3} +3x(8-x)

= 3x^{2}(8-x)^{2}[-x+8-x]+3[-x+8-x]

= 3(8-2x)[x^{2}(8-x)^{2}+1]

To find the maximum, we'll set the equation to 0.

Thus, we find:

8-2x=0 => x = 4

And since y=8-x

y =8-4= 4 > y = 4

Hence, we will substitute these values into the equation to ascertain the maximum value.

= x^{3}y^{3}+3xy

= xy(x^{2}y^{2}+3)

= 4\times4((16\times16) +3)

= 16(259) = 4144

8 0
2 months ago
Read 2 more answers
two pairs of different sizes contain 34.5 liters of water altogether. when 0.68 liter of water is poured from the bigger pail in
zzz [12365]
There will still be 34.5 L of water in the two pails combined because no water is lost.
Thus the total remains 34.5 L after transferring water between them.
Let the final amount in the smaller pail be x.
Then the larger pail contains 9x.
So x + 9x = 34.5.
That simplifies to 10x = 34.5.
Dividing both sides by 10 gives x = 3.45.
Therefore the smaller pail held 3.45 L at the end.
Because 0.68 L was poured into it, its initial volume was 2.77 L (3.45 minus 0.68)
We can also deduce the larger pail initially contained 31.73 L
(either 35 minus 2.77, or 9 times 3.45 plus 0.68)
6 0
1 month ago
an auto transport truck holds 12 cars. A car dealer plans to bring in 1006 new cars in June and July. if an auto transport truck
tester [12383]

Divide 1006 by 12

1006 / 12 = 83.833

This results in 83 complete trucks

83 * 12 = 996

Hence, 10 cars will be in the final truck

5 0
2 months ago
Read 2 more answers
Use the normal approximation to the binomial distribution to answer this question. Fifteen percent of all students at a large un
AnnZ [12381]

Answer: 0.1289

Step-by-step explanation:

Given: The proportion of students absent on Mondays at a large university.: p=0.15

Sample size: n=12

Mean: \mu=np=12\times0.15=1.8

Standard deviation = \sigma=\sqrt{np(1-p)}

\Rightarrow\ \sigma=\sqrt{12(0.15)(1-0.15)}=1.23693168769\approx1.2369

Let x represent a binomial variable.

Referencing the standard normal distribution table,

P(x=4)=P(x\leq4)-P(x\leq3) (1)

Z score for normal distribution:-

z=\dfrac{x-\mu}{\sigma}

For x=4

z=\dfrac{4-1.8}{1.2369}\approx1.78

For x=3

z=\dfrac{3-1.8}{1.2369}\approx0.97

Thus, from (1)

P(x=4)=P(z\leq1.78)-P(z\leq0.97)\\\\=0.962462-0.8339768\approx0.1289

Consequently, the likelihood of four students being absent = 0.1289

3 0
2 months ago
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