an auto transport truck holds 12 cars. A car dealer plans to bring in 1006 new cars in June and July. if an auto transport truck
2 answers:
Answer:
The last truck will have 10 cars and the total number of truckloads needed is 84
Step-by-step explanation:
Given: An auto transport truck accommodates 12 cars. A car dealer intends to import 1006 new cars in June and July.
To Determine: If every auto transport truck is filled on each delivery, except for the last one, how many complete truckloads will be necessary and how many cars will be in the final truck?
Solution:
Let the number of truckloads be denoted as x
Each truckload can carry 12 cars
Thus, x truckloads have the capacity for 12x cars
Since there are 1006 cars total
So, 12x = 1006
This leads to a total of 83 fully loaded truckloads,
for one truck can carry 12 cars
So, 83 truckloads can carry = 12 * 83 = 996 cars
Therefore, the remaining cars equal 1006 - 996 = 10 cars
Thus, an additional truckload is necessary to transport these 10 cars.
Consequently, the last truck will hold 10 cars
In total, the required number of truckloads is 83 + 1 = 84
Thus, the last truckload will contain 10 cars, making a total of 84 truckloads needed.
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Answer:
a.[144;158]$
b. The parameter being estimated is the average weekly food expenses of American families.
Step-by-step explanation:
Hello!
The variable studied here represents "Weekly food expenses incurred by an American family"($)
From a sample of n=1014 American families, the sample mean is x[bar]=$151
It is indicated that for the 95% confidence interval, the margin of error is ±$7
a.
The estimated confidence interval for the population mean is formed as "estimator ± margin of error." In a Standard Normal distribution, the confidence interval formula is:
[x[bar]±*(δ/√n)]
For the provided sample, we have:
[151±7]
The lower limit equates to 144$
The upper limit amounts to 158$
b.
The parameter being contemplated is the average weekly food expenses of American families.
The confidence level for this interval reflects the likelihood that if 100 such intervals were constructed, approximately 95 would encompass the true value of the population mean we aim to estimate.
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