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sergey
2 months ago
8

What is 72.1 repeating as a fraction

Mathematics
2 answers:
Leona [12.6K]2 months ago
6 0

Assume

x=72.111...

Scale x by an appropriate power of 10 so the non-integer portion lines up:

10x=721.111..


Now subtract x from \\10x


10x-x=721.111-72.111=649


This removes the repeating decimal bits


\\9x=649


Isolate x


Divide both sides by 9


9x/9=649/9


x=649/9


Hence


So the result is


The fraction is \frac{649}{9}


tester [12.3K]2 months ago
4 0
x=72.\overline{1}\\
10x=721.\overline{1}\\
10x-x=721.\overline{1}-72.\overline{1}\\
9x=649\\
x=\dfrac{649}{9}
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One of your peers claims that boys do better in math classes than girls. Together you run two independent simple random samples
babunello [11817]

Answer:

Step-by-step explanation:

Hello!

To determine whether boys excel in math classes compared to girls, two random samples were collected:

Sample 1

X₁: score achieved by a boy in calculus

n₁= 15

X[bar]₁= 82.3%

S₁= 5.6%

Sample 2

X₂: score obtained by a girl in calculus

n₂= 12

X[bar]₂= 81.2%

S₂= 6.7%

To estimate a confidence interval for the difference between the average percentages of boys and girls in calculus, it's essential that both variables come from normally distributed populations.

For utilizing a pooled variance t-test, it is also required that the population variances, though unknown, are assumed to be equal.

The confidence interval can then be calculated with:

[(X[bar]_1 - X[bar]₂) ± t_{n_1+n_2-2;1-\alpha /2} * Sa*\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }]

Sa= \sqrt{\frac{(n_1-1)S^2_1+(n_2-1)S^2_2}{n_1+n_2-2} } = \sqrt{\frac{14*(5.6^2)+11*(6.7^2)}{15+12-2} }= 6.108= 6.11

t_{n_1+n_2-2;1-\alpha /2}= t_{15+12-2;1-0.05}= t_{25;0.95}= 1.708

[(82.3 - 81.2) ± 1.708 * (6.11 * \sqrt{\frac{1}{15}+\frac{1}{12} }]

[-2.94; 5.14]

Using a 90% confidence level, the interval [-2.94; 5.14] is expected to encompass the true difference between the average percentages achieved by boys and girls in calculus.

I hope this is of assistance!

3 0
2 months ago
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