Answer:
(1, 1), (2, 2.333) and (3, 3.666).
Step-by-step explanation:
To solve this equation, we can select various values for x and then compute the corresponding y values.
<pFor instance, when x = 1, we find:
4*1 - 3y = 1
3y = 3
y = 1
When x = 2, we discover:
4*2 - 3y = 1
3y = 7
y = 2.333
Then for x = 3, we have:
4*3 - 3y = 1
3y = 11
y = 3.666
Therefore, the coordinates we will plot are (1, 1), (2, 2.333), and (3, 3.666).
Refer to the attached image for the plot.
D1,..,d9 = 0,0,2,2,2,3,4,6,8 //there are 9 values, presented in ascending order
Q2 (median) = d5 = 2 //middle value
Q1 = (d2+d3) / 2 = (0+2)/2 = 1
(Q1 represents the median of d1,d2,d3,d4, but as there is no singular middle element among four, the average is computed)
Q3 = (d7+d8) / 2 = (4+6)/2 = 5
interquartile range = IQR = Q3 - Q1 = 5 -1 = 4
final answer: 4
A. True. The presence of a significant outlier greater than the main group increases the mean, whereas a substantial outlier lower than the main group decreases it. B. False. Outliers distort the true mean's value. In cases where a trimmed mean is considered, the resulting mean may be correct. When outliers exist, using the median is advisable; for instance, the sale of expensive properties significantly affects the mean home prices, hence the term "median home price" is preferred. C. False. The standard deviation decreases because it indicates how data is spread. An outlier leads to greater spread, resulting in a higher standard deviation, which diminishes when the outlier is discarded as the data becomes more centralized. D. False. This assertion holds for normally distributed data that conforms to a bell curve and is centered around the mean; skewed distributions do not follow this principle. E. True. When data is described as "skewed to the right," it implies a large outlier extending the right-side tail more than anticipated, pulling the mean higher while leaving the median unchanged, causing the mean to exceed the median. This concept aligns with statement A. In conclusion, the true responses are A and E, therefore there are two correct answers.
