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natali 33
7 days ago
9

Determine the value of base x if (211)x = (6A)16

Mathematics
1 answer:
AnnZ [9K]7 days ago
4 0
This equation can be solved with two solutions, corresponding to x=7 and x=-\dfrac{15}2.
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A recent survey concluded that the proportion of american teenagers who have a cell phone is 0.27. the true population proportio
Svet_ta [9500]

Answer:

The average for the sampling distribution of the sample proportion is 0.29

The standard deviation for this sampling distribution is 0.01435

Step-by-step explanation:

The mean of the sampling distribution for the sample proportion equals the actual population proportion, which is p = 0.29 in this scenario.

The standard deviation for the sampling distribution of the sample proportion is computed as follows;

\sqrt{\frac{p(1-p)}{n} }

Utilizing the provided values;

p = 0.29

1 - p = 0.71

n = 1000

The standard deviation computes to;

\sqrt{\frac{(0.29)(1-0.29)}{1000} } \\

Thus, the standard deviation is 0.01435.

4 0
21 day ago
Rita is spending more time at home to study and practice math. Her efforts are finally paying off. On her first assessment she s
PIT_PIT [9117]

Response

After her seventh assessment, she will score above 85.

Explanation

We can represent this situation through a linear equation.

On her initial assessment, Rita scored 58, providing the first point (1, 58).

On her second assessment, Rita earned 63, making our second point (2, 63).

To calculate the rate, known as the slope of our line, we utilize the slope formula:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

where

(x_{1},y_{1}) signifies the coordinates for the first point

and (x_{2},y_{2}) represents the coordinates for the second point.

From these points, we can establish that x_{1}=1, y_{1}=58, x_{2}=2, y_{2}=63. We will input the values into our slope equation:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m=\frac{63-58}{2-1}

m=\frac{5}{1}

m=5

Now, we recognize that Rita's score grows by 5 points with every assessment.

To finalize the equation of our line, we apply the point-slope formula:

y-y_{1}=m(x-x_{1})

y-58=5(x-1)

y-58=5x-5

y=5x+53

Ultimately, we substitute y with 85 in our equation and solve for x to determine on which assessment she will achieve a score higher than 85:

85=5x+53

32=5x

x=\frac{32}{5}

x=6.4

Since a score of 0.4 assessments is not possible, she will exceed 85 after her seventh assessment.


3 0
19 days ago
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Consider the system of equations. y = 3x + 2 y = − 2 3 x − 4 Explain why these particular equations can be graphed immediately.
Inessa [9000]
It’s straightforward, as you already have the slope and y-intercepts for each equation, enabling easy graphing.

I hope this is helpful <3
5 0
1 month ago
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Classify the following triangle check all that apply ?APEX
Svet_ta [9500]
This triangle is both acute and equilateral.
It consists of three angles that are all acute, as well as having equal sides and angles.
3 0
23 days ago
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What is the greatest common factor of 36, 34, and 22?
zzz [9080]
The factors of 36 include: 1, 2, 3, 4, 6, 9, 12, 18, 36.
For 34, the factors are: 1, 2, 17, 34.
The factors of 22 are: 1, 2, 11, 22.
The greatest common factor (GCF) is 2.
7 0
1 month ago
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