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1 month ago

Estimate. then find the product 1374 x 6

Mathematics

1 answer:

Svet_ta [12.7K]1 month ago

5 0

The estimation (1370 multiplied by 6) gives 8,220, whereas the actual product (1374 multiplied by 6) results in 8,224.

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Grace is comparing cell phone plans. A prepaid phone plan costs $0.20 per minute and has no monthly fee. A contracted phone plan

lawyer [12517]

Answer:

The graph for the prepaid plan will exhibit a steeper slope and a lower y-intercept.

I trust this information is correct.

Step-by-step explanation:

prepaid plan: y =.20x

contracted plan: y =.02x + 50

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2 months ago

Read 2 more answers

Toby goes on holiday to Geneva, Switzerland. In Geneva, Toby sees a watch costing 193.75 CHF (Swiss Francs). In Manchester, An i

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1.55 CHF =?1 The price of the watch in Geneva is 1.55 CHF =?1 while 193 CHF =??1, which can be designated as x. Setting up a proportion, we cross-multiply, resulting in 1.55x = 193. Dividing by 1.55, we find x = 124.52 in x units. However, Manchester merchants are pricing it at 143 x units, so the difference is 143 - 124.52 = 18.48 units more expensive in Manchester.

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1 month ago

The number of "destination weddings" has skyrocketed in recent years. For example, many couples are opting to have their wedding

zzz [12365]

Answer:

Based on the findings, we infer that the average cost of a wedding is lower than the $30,000 that was initially suggested.

Step-by-step explanation:

The following data set is provided: (in thousands)

29100, 28500, 28800, 29400, 29800, 29800, 30100, 30600

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ denotes data points, $\bar{x}$ represents the mean, and n indicates the number of samples.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{236100}{8} = 29512.5$

The sum of squares of the differences equals 3408750

$S.D = \sqrt{\frac{3408750}{7}} = 697.82$

The population mean, μ = $30,000

The sample mean, $\bar{x}$ = $29512.5

Sample size, n = 8

Alpha, α = 0.05

Sample standard deviation, s = $697.82

Initially, we formulate the null hypothesis and the alternative hypothesis.

$H_{0}: \mu = 30000\text{ dollars}\\H_A: \mu < 30000\text{ dollars}$ A one-tailed t-test will be conducted for this analysis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

$t_{stat} = \displaystyle\frac{29512.5 - 30000}{\frac{697.82}{\sqrt{8}} } = -1.975$

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$t_{critical} \text{ at 0.05 level of significance, 7 degree of freedom } = -1.894$

$t_{stat} < t_{critical}$

Thus, we conclude that the average wedding cost is indeed less than the advertised $30,000.

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8 0

2 months ago