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anyanavicka
7 days ago
9

A bag contains 15 dark chocolates, 16 caramel chocolates, and 19 milk chocolates. The probability that Amber’s teacher distribut

es the chocolates among her students is 0.4.
If the teacher offers Amber a chocolate from the bag, the probability that she randomly picks either a caramel chocolate or a dark chocolate is
Mathematics
2 answers:
Inessa [9K]7 days ago
7 0
To calculate, begin by determining the total number of sweets: 15 + 16 + 19 equals 50. Next, combine the amounts of caramel and dark chocolates: 16 + 15 results in 31. For the probability, create a fraction where the numerator consists of the combination of caramel with dark chocolates, and the denominator is the total number of chocolates: 31/50. Thus, Amber has a 31 out of 50 likelihood of selecting either a caramel chocolate or a dark chocolate.
babunello [8.4K]7 days ago
5 0

Response:

31/50

Detailed explanation:

If Amber is offered a chocolate from the bag, her chance of randomly choosing between a caramel chocolate or a dark chocolate is 31/50.

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Answer: To remove fractions prior to solving, each term in the equation must be multiplied by 4.

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Consider the given expression:

-\frac{3}{4}m-\frac{1}{2}=2+\frac{1}{4}m

It is essential to simplify this before attempting to solve it.

Since the denominators differ, identifying the Least Common Denominator (LCD) is necessary.

Break down the denominators into their prime components:

4=2*2=2^2\\2=2

Select 2^2, as it possesses the greatest exponent. Thus:

LCD=2^2=4

Ultimately, to remove the fractions before solving, multiply both sides by 4:

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2(4x-11) = 10

Method 1:
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Method 2:

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