What is the greatest perfect square that is a factor of 396?

 x = 27 + 3 √ 129/ 4, 27 − 3 √ 129/ 4

Please note: the entire equation mentioned is divided by 4, not only the last term. 

 x approximates to 15.26836251, − 1.76836251

That concludes my response. I hope this is helpful. You will still need to work on finding y and z, which can be quite challenging:)

An even function can be reflected over the y-axis and still remain unchanged.
Example: y=x^2
On the other hand, an odd function can be reflected around the origin and also remains unchanged.
Example: y=x^3


A straightforward method to determine this is:

if f(x) is even, then f(-x)=f(x)
if f(x) is odd, then f(-x)=-f(x)


Hence, for an even function
substitute -x in for each and check for equivalence
make sure to fully expand the expressions
g(x)=(x-1)^2+1=x^2-2x+1+1=x^2-2x+2 is the original expression
g(x)=(x-1)^2+1
g(-x)=(-x-1)^2+1
g(-x)=(1)(x+1)^2+1
g(-x)=x^2+2x+1+1
g(-x)=x^2+2x+2
Not the same, as the original contains -2x
Therefore, it is not even
g(x)=2x^2+1
g(-x)=2(-x)^2+1
g(-x)=2x^2+1
It matches, hence it is even
g(x)=4x+2
g(-x)=4(-x)+2
g(-x)=-4x+2
Not equivalent, thus not even
g(x)=2x
g(-x)=2(-x)
g(-x)=-2x
Not equal, therefore not even



g(x)=2x²+1 is the confirmed even function.

Answer : y>0

f(x) = 9*2^x

This function is exponential in form

Substituting positive numbers for x yields positive y values

Substituting negative numbers for x also results in positive y values

Therefore, y remains positive regardless of the value of x.

The range comprises all possible y outputs of the function

Since y is always positive, the range is y > 0

Answer:

Tina's overall average speed for the journey is 56 km/h.

Step-by-step explanation:

Sean's travel time from Town A to Town B is 4 hours.

Sean's average speed is 70 km/h.

Using the motion equation, s = ut + 0.5 at², we can find:
Time, t = 4 hours.

Initial speed, u = 70 km/hr.

Acceleration, a = 0 m/s².

Replacing the variables:

      s = ut + 0.5 at²

      s = 70 x 4 + 0.5 x 0 x 4²

      s = 280 km

The distance from Town A to Town B is 280 km.

Tina's travel time exceeds Sean's by 1 hour.

Tina's time to travel from Town A to Town B is 4 + 1 = 5 hours.

Again applying the motion equation, s = ut + 0.5 at²:

Time, t = 5 hours.

Distance, s = 280 km.

Acceleration, a = 0 m/s².

Putting in values:

      s = ut + 0.5 at²

      280 = u x 5 + 0.5 x 0 x 5²

      u = 56 km/hr.

Tina's overall average speed is thus 56 km/h.

Response:  1232

Detailed breakdown:  ( 8x10 -3) x(2x10 -4)  

( 8x10 -3) = 77

(2x10 -4) = 16

77 x 16 = 1232

Final answer = 1232