Averages indicate 95 pounds per passenger with a standard deviation of 35 pounds, so multiplying this by the total passenger count of 200 gives the result of:
total average = 95 * 200 = 19,000
total std dev = 35 * 200 = 7,000
To find the z score:
z = (x – u) / s
here x represents the observed value = exceeding 20,000; u stands for the mean value = 19,000; s is the standard deviation = 7,000
z = (20,000 – 19,000) / 7,000
z = 0.143
Referring to distribution tables,
P (z = 0.14) = 0.5557
<span>Thus, there is a 55.57% likelihood that the total weight will surpass the 20,000-pound threshold</span>
