Answer:
118.2°
Step-by-step explanation:
Dos líneas paralelas x e y son cortadas por la transversal w (ver el diagrama adjunto).
Se forman 8 ángulos (denominados 1, 2, 3, 4, 5, 6, 7 y 8).
Los ángulos 1 y 6 son ángulos del mismo lado cuando dos líneas paralelas x e y son cortadas por la transversal w.
Dos ángulos del mismo lado son suplementarios (suman 180°). Esto significa
Dado 
por lo que
I'm not precisely certain what coordinates are anticipated, yet the 270° originating from the loading platform would appear as shown in the image below, and indeed, all "standard position" angles are measured counterclockwise.
Answer:
Step-by-step breakdown:
You may consider a structure like the following while keeping in mind your specific notation.
1. | ~( (~Q ->~R) v (R & ~Q) ) Assume
2. | | ~(~Q ->~R) Assume
3. | | | ~(R & ~Q) Assume
4. | | | ~R v Q 3, De Morgan
5. | | | ~Q -> ~R 4 Material implication
6. | | | # 2, 5 Results in a contradiction
7. | | R & ~Q 3-6 indirect proof outcome
8. | ~(~Q ->~R) -> (R & ~Q ) 2-7 Discharging the conditional proof
9. | (~Q ->~R) v (R & ~Q) 8 Material implication derived
10 | # 1,9 Results in contradiction
11. (~Q ->~R) v (R & ~Q) 1-10 Completion via indirect proof
The range of the function on the graph includes all numbers greater than or equal to -3.
0.183. This problem addresses Binomial Probability. The formula is nCx × p^x × q^(n - x), where p = 0.72 and q = 1 - p = 0.28. With x representing the number of successes equal to 9 and n being 10, we are calculating the probability that at least nine out of ten people utilized an online travel website for booking. At least 9 out of 10 translates to x ≥ 9, so we calculate P(x ≥ 9) for x = 9 and x = 10. This leads to: P(x ≥ 9) = 10C9 × (0.72^9 × 0.28^(10 - 9)) + 10C10 × (0.72^10 × 0.28^(10 - 10)), resulting in approximately P(x ≥ 9) = 0.183.
