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Marizza181
9 days ago
15

A silent auction was held for a quilt donated for charity. Fifteen bids that were drawn randomly are listed here. What percentil

e is the bid value of $105? $85 $240 $120 $60 $315 $190 $145 $105 $285 $260 $95 $215 $235 $175 $155
Mathematics
2 answers:
Inessa [9K]9 days ago
8 0

Outcome:

The result is the 27th percentile, but for quiz purposes, you will need to submit it as the 20th percentile

Step-by-step explanation:

Leona [9.2K]9 days ago
7 0

The provided values are

$85 $240 $120 $60 $315 $190 $145 $105 $285 $260 $95 $215 $235 $175 $155

To start, we will arrange these in ascending order

resulting in

$60 $85 $95  $105  $120  $145 $155 $175 $190 $215 $235 $240 $260 $285 $315

The total count is 15

the position of 105 is 4

Now, we can calculate the percentile

=\frac{4}{15} *100

Thus, the percentile for the bid of $105 is 26.667%...........Response

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Malik randomly picked two numbers from 1 to 9 (Includin 1 and 9). the same number could be picked more than once. The first of t
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Response:

2/9 = 0.22

Clarification:

There are two ways to select the first number that is odd and less than 5: 1 and 3.

For each of these, the second number drawn can be any of the values from 1 to 9, giving us a total of 18 options.

Out of these, the only pairs that result in a sum less than 5 are (1,1), (1,2), (1,3), and (3,1). Thus we have 4 combinations from the total of 18:

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9 days ago
While driving from his home to his workplace, Chris has to pass through two traffic lights. The general probability of getting a
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7 days ago
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tester [8842]

Answer:

Part A. At least 6 hours

Part B. In less than 2.5 hours, Elijah will fall behind Mercedes

Part C. In over 2.5 hours, Elijah will lead Aubrey

Step-by-step explanation:

D = distance

v = speed

t = time

Formula connecting D, v, and t:

D=v\cdot t

Part A.

Steve's speed: v=3.5\ mph

Distance: a minimum of 21 miles

Time: unknown, so

3.5\cdot t\ge 21\\ \\35t\ge 210\ [\text{Multiplied by 10}]\\ \\t\ge \dfrac{210}{35}\\ \\t\ge \dfrac{30}{5}\\ \\t\ge 6

It would require Steve a minimum of 6 hours to traverse at least 21 miles on Day 1.

Part B.

Mercedes's speed: v_M=2.4\ mph

Elijah's speed: v_E=3.2\ mph

Elijah's Distance walked: D_E miles

Mercedes's Distance walked: D_M miles

Time: x hours

Mercedes is 2 miles ahead, therefore

D_E=3.2x\\ \\D_M=2.4x+2

Elijah will trail behind until

D_E

In 2.5 hours, Elijah will close the gap on Mercedes, and in less than 2.5 hours, Elijah will trail behind her.

Part C.

Aubrey's speed: v_M=3\ mph

Elijah's speed: v_E=3.2\ mph

Elijah's Distance walked: D_E miles

Aubrey's Distance walked: D_A miles

Time: x hours

At the beginning of Day 3, Elijah starts from Mile 42, while Aubrey begins at Mile 42.5.

D_E=42+3.2x\\ \\D_A=42.5+3x

Elijah will be ahead of Aubrey when

D_E>D_A\\ \\42+3.2x> 42.5+3x\\ \\3.2x-3x>42.5-42\\ \\0.2x>0.5\\ \\2x>5\ [\text{Multiplied by 10}]\\ \\x>\dfrac{5}{2}\\ \\x>2.5\ hours

In 2.5 hours, Elijah will surpass Aubrey, and after more than 2.5 hours, Elijah will outpace Aubrey.

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1 month ago
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It exhibits a zero slope.

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