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lakkis
6 days ago
9

3x+8+2ax≥3ax−4a what is x?

Mathematics
2 answers:
zzz [9K]6 days ago
7 0
X≥
- \frac {4 (2 + a)}{3 - a}
to resolve the inequality, identify the roots and establish testing intervals.
zzz [9K]6 days ago
6 0

Response:

\text{x}\geq \frac{-4(2+\text{a})}{(3-\text{a})}

Step-by-step breakdown:

Given: the inequality 3x+8+2ax≥3ax−4a

Goal: to determine the value of x

Solution:

within the provided inequality

3\text{x}+8+2\text{a}\text{x}\geq 3\text{a}\text{x}-4\text{a}

3\text{x}+2\text{a}\text{x}-3\text{a}\text{x}\geq -4\text{a}-8

\text{x}(3+2\text{a}-3\text{a})\geq -8-4\text{a}

\text{x}(3-\text{a})\geq -8-4\text{a}

\text{x}\geq \frac{-8-4\text{a}}{(3-\text{a})}

\text{x}\geq \frac{-4(2+\text{a})}{(3-\text{a})}

thus the value of \text{x}\geq \frac{-4(2+\text{a})}{(3-\text{a})}

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Hello!

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