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gavmur
1 month ago
9

A motorist inflates the tires of her car to a pressure of 180 kPa on a day when the temperature is -8.0° C. When she arrives at

her destination, the tire pressure has increased to 245 kPa. What is the temperature of the tires if we assume that the tires do not expand?
Physics
1 answer:
kicyunya [3.2K]1 month ago
4 0
Utilize Gay-Lussac's law: P/T = constant. Here, P refers to pressure and T indicates temperature; the ratio P/T must remain unchanged. The initial values of pressure and temperature provided are: P = 180 kPa, T = -8.0°C, equating to 265.15K. Subsequently, for the final measurements: P = 245 kPa, T =?. We will set the initial and final P/T values equal and solve for T: 180/265.15 = 245/T, leading to T = 361K.
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Answer:

10000 V

0.00225988700565 m²

8\times 10^{-12}\ F

Explanation:

E = Electric field = 4\times 10^6\ V/m

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\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

The potential difference is calculated as

V=Ed\\\Rightarrow V=4\times 10^6\times 2.5\times 10^{-3}\\\Rightarrow V=10000\ V

The potential difference across the plates amounts to 10000 V

Area is determined by

A=\dfrac{Q}{\epsilon_0E}\\\Rightarrow A=\dfrac{80\times 10^{-9}}{8.85\times 10^{-12}\times 4\times 10^6}\\\Rightarrow A=0.00225988700565\ m^2

The area of each plate measures 0.00225988700565 m²

Capacitance is determined by

C=\dfrac{\epsilon_0A}{d}\\\Rightarrow C=\dfrac{8.85\times 10^{-12}\times 0.00225988700565}{2.5\times 10^{-3}}\\\Rightarrow C=8\times 10^{-12}\ F

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1 month ago
A window washer on a hanging platform cleans the outside of windows on a skyscraper. The washer hoists the platform up the side
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Setting up the force equilibrium for the configuration:

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We examine only small amplitude oscillations (as in this scenario), which keeps the angle θ sufficiently small. In such situations, it's important to note that the pendulum's motion can be described by the equation:

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Answer:

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