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gavmur
3 months ago
9

A motorist inflates the tires of her car to a pressure of 180 kPa on a day when the temperature is -8.0° C. When she arrives at

her destination, the tire pressure has increased to 245 kPa. What is the temperature of the tires if we assume that the tires do not expand?
Physics
1 answer:
kicyunya [3.2K]3 months ago
4 0
Utilize Gay-Lussac's law: P/T = constant. Here, P refers to pressure and T indicates temperature; the ratio P/T must remain unchanged. The initial values of pressure and temperature provided are: P = 180 kPa, T = -8.0°C, equating to 265.15K. Subsequently, for the final measurements: P = 245 kPa, T =?. We will set the initial and final P/T values equal and solve for T: 180/265.15 = 245/T, leading to T = 361K.
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A vacuum tube diode consists of concentric cylindrical electrodes, the negative cathode and the positive anode. Because of the a
serg [3582]

Answer:

   C = 4,174 10³ V / m^{3/4},  E = 7.19 10² / ∛x,    E = 1.5  10³ N/C

Explanation:

In this problem, we are tasked with determining the constant value and the generated electric field.

We will begin with computing the constant C:

           V = C x^{4/3}

           C = V / x^{4/3}

            C = 220 / (11 10⁻²)^{4/3}

            C = 4,174 10³ V / m^{3/4}

Next, we will find the electric field by utilizing the formula:

            V = E dx

             E = dx / V

             E = ∫ dx / C x^{4/3}

            E = 1 / C  x^{-1/3} / (- 1/3)

            E = 1 / C (-3 / x^{1/3})

We consider the evaluation from the lower limit x = 0 where E = E₀ = 0 to the upper limit x = x, resulting in E = E:

            E = 3 / C     (0- (-1 / x^{1/3}))

            E = 3 / 4,174 10³   (1 / x^{1/3})

           E = 7.19 10² / ∛x

Substituting x = 0.110 cm:

          E = 7.19 10² /∛0.11

          E = 1.5  10³ N/C

6 0
3 months ago
Suppose Sammy Sosa hits a home run which travels 361. ft (110. m). Leaving the bat at 50 degrees above the horizontal, how high
Yuliya22 [3333]

Response:

The horizontal span of Sosa is 276.526 ft or 84.28 meters.

Explanation:

As illustrated in the diagram, let point O denote Sosa's starting position. She travels 361 ft at a 50-degree angle relative to the horizontal.

sin 50 = \frac{OM}{OP}

0.7660 = h / 361

h = 276.526 ft

h = 84.28 meters

The horizontal distance of Sosa is 276.526 ft or 84.28 meters.

5 0
3 months ago
Two electrodes, separated by a distance d, in a vacuum are maintained at a constant potential difference. An electron, accelerat
Yuliya22 [3333]

Answer:

Explanation:

The distance between the electrodes is denoted as d.

The kinetic energy of the electron is represented as Ek when the electrodes are positioned at a distance of "d" apart.

Our goal is to determine the kinetic energy when they are separated by a distance of d/3.

K.E = ½mv²

It’s important to note that the mass remains constant; only velocity varies.

Additionally,

K.E = Work done by the electron

K.E = F × d

K.E = W = ma × d

Assuming constant acceleration

Hence, m and a are fixed,

therefore,

K.E is directly related to d

Thus, as d increases, K.E increases, and conversely, when d decreases, K.E decreases.

Consequently,

K.E_1 / d_1 = K.E_2 / d_2

With K.E_1 equating to E_k

and d_1 being d

while d_2 is represented as d/3

This leads to K.E_2 = K.E_1 / d_1 × d_2

Thus, K.E_2 = E_k × ⅓d / d

Finally,

K.E_2 = ⅓E_k

Therefore, the resultant kinetic energy is one third of the original E_k

7 0
2 months ago
A baseball is hit high into the upper bleachers of left field. Over its entire flight the work done by gravity and the work done
serg [3582]

Answer:

Explanation:

As the baseball ascends, gravitational forces as well as air resistance act downward, whereas the displacement is moving upward which results in an angle of 180° between the force and displacement. Therefore, the work done by both the gravitational force and air resistance is negative, confirming option (d) as accurate.

6 0
3 months ago
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