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vodka
2 months ago
13

A beam of electrons moves at right angles to a magnetic field of 4.5 × 10-2 tesla. If the electrons have a velocity of 6.5 × 106

meters/second, what is the force acting on the electrons? The value of q = -1.6 × 10-19 coulombs.
(A)-2.9 × 106 N
(B)-3.9 × 10-14 N
(C)-4.9 × 10-14 N
(D)-6.5 × 10-13 N
Physics
2 answers:
Softa [3K]2 months ago
6 0
Greetings!

Using the formula F = Bqv sin theta, we define F as Force, B as magnetic flux density, q as charge, v as velocity, and theta as the angle created by the moving electrons in relation to the magnetic field.

^^^You can compute the force using that equation^^^

In conclusion, your result would MOST LIKELY be "B".

"<span>-3.9 × 10-14 N"
</span>
<span>I trust my response has been beneficial. Thank you for your question. We look forward to assisting with more inquiries. Have a wonderful day ahead!:</span>
ValentinkaMS [3.4K]2 months ago
6 0

Explanation:

Provided data includes

the Magnetic field, B=4.5\times 10^{-2}\ T

the Velocity of electrons, v=6.5\times 10^6\ m/s

the Charge, q=-1.6\times 10^{-19}\ C

and the Magnetic force F=q(v\times B)

F=-1.6\times 10^{-19}\ C\times 6.5\times 10^6\ m/s\times 4.5\times 10^{-2}\ T

Thus, F=-4.68\times 10^{-14}\ N

The nearest answer can be option (b) " -3.9\times 10^{-14}\ N "

Consequently, this is the solution sought.

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