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goldenfox
1 month ago
5

A common small-molecular weight (and therefore fast diffusing for an organic molecule) ingredient in perfumes is vanillin, the p

rimary component of vanilla bean extract (molecular weight = 152). the d for vanillin in air is 0.114 cm2/s. if i open a bottle of vanilla on the other side of the room 3 meters away, and the air is still so there is no convection, about how long would i have to wait before i could expect to smell the vanilla?
Physics
2 answers:
Softa [3K]1 month ago
7 0
What's the response shshshsbshsbsbs sbo
kicyunya [3.2K]1 month ago
4 0

Answer:

2.54 seconds

Explanation:

To find the necessary information:

molecular weight = 152 g/mol

diffusion coefficient = 0.114 cm²/s

Distance = 3 meters

The key principle here is Fick's Law of diffusion, which states that the flux correlates directly with the concentration difference. Essentially:

where dc = the change in concentration

D = diffusion coefficient

Dx = distance change, cm

Solving yields:

j = dc/3 (-0.114)

Therefore, t = 2.54 seconds

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Ellen does an experiment by releasing a ball from a height of 1 m above each floor in a tall building. She records the time it t
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The question Ellen is likely exploring is "In what way does distance influence the gravitational force acting on objects?"

Explanation:

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If the satellite was placed in an orbit three times farther away, about how long would it take to orbit the Earth once? Answer i
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Kepler's third law, referred to as the law of harmonies, is used to calculate the orbital period and radius of a planet based on the dimensions and periods of another planet. This relationship is directly proportional to the square of the period and inversely proportional to the cube of the distance. Therefore, when the distance is tripled ((3D)^3), the period should increase to the square root of 27 times 5.20 times the initial period,
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18 days ago
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At time t=0 a proton is a distance of 0.360 m from a very large insulating sheet of charge and is moving parallel to the sheet w
serg [3582]

Explanation:

The formula for the electric field produced by an infinite sheet of charge is outlined below.

               E = \frac{\sigma}{2 \epsilon_{o}}

where,   \sigma is the surface charge density

Following this, the formula for the electric force acting on a proton is given as:

             F = eE

where,    e is the charge of a proton

According to Newton's second law of motion, the overall force on the proton can be expressed as follows.

                       F = ma

                 a = \frac{eE}{m}

                    = \frac{e(\frac{\sigma}{2 \epsilon_{o}})}{m}

                     = \frac{e \sigma}{2m \epsilon_{o}}

According to kinematic equations, the proton's speed in the perpendicular direction can be described as follows.

              v_{f} = v_{i} + at

                     = (0 m/s) + \frac{e \sigma}{2 m \epsilon_{o}}t

                     = \frac{1.6 \times 10^{-19}C \times 2.34 \times 10^{-9} C/m^{2} \times 5.40 \times 10^{-8}s}{2 \times (1.67 \times 10^{-27} kg)(8.85 \times 10^{-12} C^{2}/Nm^{2}}

                     = 683.974 m/s

Thus, the overall speed of the proton can be calculated as follows.

                v' = \sqrt{(960 m/s)^{2} + (683.974 m/s)^{2}}

                    = \sqrt{921600 + 467820.43}

                    = \sqrt{1389420.43}

                    = 1178.73 m/s

Consequently, we conclude that the proton's speed is 1178.73 m/s.

3 0
19 days ago
A girl drops a pebble from a high cliff into a lake far below. She sees the splash of the pebble hitting the water 2.00s later.
Yuliya22 [3333]

Answer:

19.62 ms

Explanation:

t = Time taken = 2 s

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s² (we take downward direction as positive)

v=u+at\\\Rightarrow v=0+9.81\times 2\\\Rightarrow v=19.62\ m/sUsing the equations of motion

The pebble's speed upon contact with the water is 19.62 ms

3 0
15 days ago
The deflection plates in an oscilloscope are 10 cm by 2 cm with a gap distance of 1 mm. A 100 volt potential difference is sudde
Maru [3345]

Explanation:

Data provided:

Area A = 10 cm×2 cm = 20×10⁻⁴ m²

Separation distance d between the plates = 1 mm = 1×10⁻³ m

Battery voltage, or emf = 100 V

Resistance = 1025 ohm

Solution:

In an RC circuit, the voltage across the plates varies with time t. At the outset, the voltage matches that of the battery, V₀ = emf = 100V. However, after a certain time t, both the resistance and capacitance alter this, leading to a final voltage V expressed as

V = V_{0}(1-e^{\frac{-t}{RC} } )\\\frac{V}{V_{0} } = 1-e(^{\frac{-t}{RC} }) \\e^{\frac{-t}{RC} } = 1- \frac{V}{V_{0} }

Applying the natural logarithm to both sides,

e^{\frac{-t}{RC} } = 1- \frac{V}{V_{0} } \\\frac{-t}{RC} = ln(1-\frac{V}{V_{0} } )\\t = -RCln(1 - \frac{V}{V_{0} })

t = -RC ln (1-\frac{V}{V_{0} })        (1)

Next, we can determine the capacitance using the plates' area.

C = ε₀A/d

  = \frac{(8.85*10^{-12))} (20*10^{-4}) }{1*10^{-3} }

  = 18×10⁻¹²F

We can now find the time it takes for the voltage to drop from 100 to 55 V by substituting C, V₀, V, and R values into equation (1)

t = -RC ln (1-\frac{V}{V_{0} })

 = -(1025Ω)(18×10⁻¹² F) ln( 1 - 55/100)

 = 15×10⁻⁹s

= 15 ns

5 0
14 days ago
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