The question Ellen is likely exploring is "In what way does distance influence the gravitational force acting on objects?"
Explanation:
Kepler's third law, referred to as the law of harmonies, is used to calculate the orbital period and radius of a planet based on the dimensions and periods of another planet. This relationship is directly proportional to the square of the period and inversely proportional to the cube of the distance. Therefore, when the distance is tripled ((3D)^3), the period should increase to the square root of 27 times 5.20 times the initial period,
Explanation:
The formula for the electric field produced by an infinite sheet of charge is outlined below.
E =
where,
is the surface charge density
Following this, the formula for the electric force acting on a proton is given as:
F = eE
where, e is the charge of a proton
According to Newton's second law of motion, the overall force on the proton can be expressed as follows.
F = ma
a = 
= 
= 
According to kinematic equations, the proton's speed in the perpendicular direction can be described as follows.

= 
= 
= 683.974 m/s
Thus, the overall speed of the proton can be calculated as follows.
v' =
=

= 
= 1178.73 m/s
Consequently, we conclude that the proton's speed is 1178.73 m/s.
Answer:
19.62 ms
Explanation:
t = Time taken = 2 s
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.81 m/s² (we take downward direction as positive)
Using the equations of motion
The pebble's speed upon contact with the water is 19.62 ms
Explanation:
Data provided:
Area A = 10 cm×2 cm = 20×10⁻⁴ m²
Separation distance d between the plates = 1 mm = 1×10⁻³ m
Battery voltage, or emf = 100 V
Resistance = 1025 ohm
Solution:
In an RC circuit, the voltage across the plates varies with time t. At the outset, the voltage matches that of the battery, V₀ = emf = 100V. However, after a certain time t, both the resistance and capacitance alter this, leading to a final voltage V expressed as

Applying the natural logarithm to both sides,

(1)
Next, we can determine the capacitance using the plates' area.
C = ε₀A/d
= 
= 18×10⁻¹²F
We can now find the time it takes for the voltage to drop from 100 to 55 V by substituting C, V₀, V, and R values into equation (1)

= -(1025Ω)(18×10⁻¹² F) ln( 1 - 55/100)
= 15×10⁻⁹s
= 15 ns