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goldenfox
9 days ago
5

A common small-molecular weight (and therefore fast diffusing for an organic molecule) ingredient in perfumes is vanillin, the p

rimary component of vanilla bean extract (molecular weight = 152). the d for vanillin in air is 0.114 cm2/s. if i open a bottle of vanilla on the other side of the room 3 meters away, and the air is still so there is no convection, about how long would i have to wait before i could expect to smell the vanilla?
Physics
2 answers:
Softa [913]9 days ago
7 0
What's the response shshshsbshsbsbs sbo
kicyunya [1K]9 days ago
4 0

Answer:

2.54 seconds

Explanation:

To find the necessary information:

molecular weight = 152 g/mol

diffusion coefficient = 0.114 cm²/s

Distance = 3 meters

The key principle here is Fick's Law of diffusion, which states that the flux correlates directly with the concentration difference. Essentially:

where dc = the change in concentration

D = diffusion coefficient

Dx = distance change, cm

Solving yields:

j = dc/3 (-0.114)

Therefore, t = 2.54 seconds

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Two trains are headed towards each other on the same track unbeknownst to the engineers. One departs San Francisco. Its average
ValentinkaMS [1149]

Answer:

7.166 hours = 430 minutes.

Explanation:

As both trains are approaching each other on the same track, their relative speed is the sum of their individual speeds. Hence, the time until they intersect (and inevitably collide) is determined by how long it takes for speeds of 65 mph and 55 mph to cover the total distance of 860 miles. One train will cover part of the distance, while the other will cover the remainder. To calculate the required time, we can apply the formula:

1 hour ---> 120 miles

X ----> 860 miles; hence X = (860 miles * 1 hour)/120 miles = 43/6 hours = 7.16666 hours. To convert this into minutes, recall that 1 hour equals 60 minutes; therefore, 43/6 hours * 60 minutes/hour = 430 minutes.

7 0
1 day ago
Which pair of graphs represent the same motion of an object
Ostrovityanka [942]
The correct choice is C
3 0
15 days ago
Read 2 more answers
If a person weighs 882 N on the surface of the earth, at what altitude above the earth’s surface must they be for their weight t
Sav [1105]

Para calcular el peso utilizamos la fórmula:
F=m*g=882N

Cuando tenemos dos cuerpos, empleamos la fórmula de la gravedad general:
F=G* \frac{ M_{p}*M_{E} }{ r^{2} }
Donde:
G = constante de gravedad = 6.67* 10^{-11} m^{3} kg^{-1} s^{-2}
Mp = masa de la persona = 882 / 9.81= 89.9kg
ME = masa de la Tierra = 5.97* 10^{24} kg
r = distancia entre la Tierra y la persona

A partir de estas dos fórmulas, deducimos que los lados izquierdos son equivalentes, por lo tanto, los lados derechos también deben serlo.
m*g=G* \frac{ M_{p}*M_{E} }{ r^{2} }

Resolviendo esta ecuación para r:
r= \sqrt{G* \frac{ M_{p}*M_{E}}{M_{p}*g}
r=6371116m = 6371.116km

Esta es la distancia desde el centro de la Tierra. El radio de la Tierra es 6370km y la altura sobre la superficie es 6371.116 - 6370 = 1.116km o 1116m.

3 0
2 days ago
Which statements about inertia and centripetal force are correct? Check all that apply. Inertia is always present. Inertia cause
kicyunya [1025]
Inertia is universally present. It's important to note that inertia doesn't serve as the force keeping objects in circular paths; that role belongs to centripetal force, which is not always present. Centripetal force actively pulls objects towards the center of a circle. Both inertia and centripetal force contribute to the phenomenon of circular motion. Thank you, and enjoy your day;)
6 0
5 days ago
Read 2 more answers
Steel blocks A and B, which have equal masses, are at TA = 300 oC and T8 = 400 oC. Block C, with mc - 2mA, is at TC = 350 oC. Bl
serg [1198]

Answer:

b) TA = TB = TC

Explanation:

  • When the blocks are brought into contact and isolated from the environment, they will exchange heat until they achieve thermal equilibrium.
  • During this exchange, the hotter body will lose heat, which will be gained by the cooler body.
  • The equilibrium state will be established once this equation is satisfied:

       \Delta Q = c_{st}* m_{A} * (T_{fin} - T_{0A} ) = c_{st}* m_{B} * (T_{0B} - T_{fin} )

  • Substituting the initial temperatures T₀A = 300º C and T₀B = 400ºC, while simplifying for equal block masses mA = mB, enables us to solve for the final temperature, Tfin:

       (400 \ºC - T_{fin}) = (T_{fin} - 300 \ºC) \\ \\ 2* T_{fin} = 700\ºC\\ \\ T_{fin} = 350\ºC

  • At equilibrium, when both blocks combine, they will yield a uniform final temperature of 350ºC.
  • When block C, also at this temperature, makes contact, all three blocks will simultaneously reflect this final temperature of 350 ºC.
  • Therefore, option b) is correct.
8 0
6 days ago
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