A fruit stand has to decide what to charge for their produce. They need \$5.30$5.30dollar sign, 5, point, 30 for 111 apple and 1

Question

10 days ago

10

A fruit stand has to decide what to charge for their produce. They need \$5.30$5.30dollar sign, 5, point, 30 for 111 apple and 1

11 orange. They also need \$7.30$7.30dollar sign, 7, point, 30 for 111 apple and 222 oranges. We put this information into a system of linear equations.

Mathematics

2 answers:

Inessa [9K] · Answer 1 · 2026-03-17T14:05:26+03:00

111 apples cost $3.30 while 111 oranges are priced at $2 (1 apple roughly costs $0.03 and 1 orange around $0.02). To solve this, let us define $x as the cost for 111 apples and $y for 111 oranges. 1. Together, 111 apples and 111 oranges amount to $5.30, giving us the equation x+y=5.30. 2. For 111 apples and 222 oranges, the total comes to $7.30, forming the equation x+2y=7.30. By subtracting the first equation from the second, we find: x+2y-x-y=7.30-5.30 leading us to y=2. Plugging this back into the first equation supplies x+2=5.30, thus x=3.30. Therefore, 111 apples cost $3.30 and 111 oranges $2 (1 apple is nearly $0.03, and 1 orange approximately $0.02).

Svet_ta [9.5K] · Answer 2 · 2026-03-17T14:06:33+03:00

Svet_ta [9.5K]10 days ago

3 0

The pricing for apples is $3.30 and for oranges is $2.00.