Answer:
1. x=±4
2. t=±9
3. r=±10
4. x=±12
5. s=±5
Step-by-step explanation:
1. x^2 = 16
By extracting the square root on both sides
x=±4
2. t^2=81
Again, take the square root of each side
t=±9
3. r^2-100=0
r=±10
4. x²-144=0
We rewrite as x²=144
Applying square roots
x=±12
5. 2s²=50
s=±5 ..
Given:
The temperature recorded at 10:00 am is 8 degrees Fahrenheit.
The temperature decreases by 3 degrees Fahrenheit each hour.
To find:
The temperature at 2:00 pm on the same day.
Solution:
Let y represent the temperature after x hours since 10:00 am.
The temperature at 10:00 am serves as the initial temperature.
Thus, the y-intercept of the linear equation is 8.
The temperature reduces by 3 degrees Fahrenheit every hour.
This indicates the slope of the linear equation is -3, with the negative sign indicating a decrease.
The slope-intercept form of a linear function is indicated by
where m is the slope and b is the y-intercept.
Inserting m=-3 and y=8 into the above equation gives us the required values.
From 10:00 am to 2:00 pm spans 4 hours; therefore, substitute x=4 into the above equation.
Consequently, the temperature at 2:00 pm is -4 degrees Fahrenheit.
We are given the triangle
△ABC, with m∠A=60° and m∠C=45°, and AB=8.
To start, we will calculate all angles and sides.
Finding angle B:
The total of all angles in a triangle equals 180.
m∠A + m∠B + m∠C = 180.
Substituting the known values,
60° + m∠B + 45° = 180.
This gives us m∠B = 75°.
Calculating BC:
Using the law of sines,
We can substitute in the values.
Finding AC:
Now we'll input the values.
Calculating Perimeter:
We substitute values here as well.
Calculating Area:
Using the area formula,
we can then insert values.
...............Answer