Try this approach (refer to the attachment, which outlines three steps).
To formulate the system, it's necessary to consider the slope of each line along with at least one point from each line. The two lines will connect each plane's location to their destination airport. It's important to note that the airport's coordinates represent the intersection of these two lines, corresponding to the solution of the system. First, the slope of the line from airplane one to the airport is: m = 2; this can be observed by plotting the two points. From airplane 1's location, the rise is 8 units while the run is 4 units to reach the airport, making the slope 8 divided by 4 = 2. We then insert the slope and point (2,4) into the point-slope form: y - 4 = 2(x - 4), which can be rearranged to standard form 2x - y = 0. For airplane two, the slope to the airport is obtained by observing the vertical decrease of 3 and a horizontal increase of 9 as we move from the airport to airplane 2. We then substitute the slope and the point (15,9) into the point-slope form: y - 9 = -1/3(x - 15), which can be rearranged to the standard form: x + 3y = 42. Consequently, the system of equations is: 2x - y = 0 and x + 3y = 42. Multiplying the first equation by 3 produces a system of: 6x - 3y = 0 and x + 3y = 42. Adding these equations results in the equation 7x = 42. Thus, x = 6, and by substituting this value back into 2x - y = 0, we determine y = 12. Thus, we demonstrate that the airport's coordinates do indeed comprise the solution to our system.
The x intercept is at (12,0). To find it, start with the equation 1.5x + 4.5y = 18, and subtract 1.5x from both sides. This gives you 4.5y = -1.5x + 18. Next, divide everything by 4.5, resulting in y = -1/3x + 4. Hence, the slope of the line is -1/3, and the y intercept is at (0,4). To determine the x intercept, set y to 0. Plugging this into the equation yields: 1.5x + 4.5(0) = 18, simplifying to 1.5x = 18. Dividing both sides by 1.5 gives x = 12.
Response: a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318
Detailed explanation:
In Problem 8-4, the computer time-sharing system experiences teleport inquiries at an average rate of 0.1 per millisecond. We are tasked with determining the probabilities of the inquiries over a specific period of 50 milliseconds:
Given that
Applying the Poisson process, we find that
(a) at most 12
probability= 
(b) exactly 13
probability=
(c) more than 12
probability=
(d) exactly 20
probability=
(e) within the range of 10 to 15, inclusive
probability=
Thus, a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318
220: goodnight, mark me brainliest Explanation: Let M symbolize the count of people who drank milk, while T denotes those who consumed tea. Let x indicate the number who had both milk and tea. Consequently, the count of individuals who drank only milk is represented by n(M ∩ T') = 620 - x, and those who drank only tea is n(M' ∩ T) = 350 - x. Since 800 individuals took part, we have: 620 - x + (350 - x) + x + 50 = 800, simplifying to 1020 - x = 800. Therefore, x = 220. Thus, 220 individuals consumed both beverages.
