Answer: g(x) > h(x) when x = -1.
For x greater than zero, g(x) is greater than h(x).
For x less than zero, g(x) is greater than h(x).
Step-by-step explanation:
Given the functions:
and 
At x = 0,
and 
. Therefore, g(0) equals h(0).
Hence, statements claiming that for all x, g(x) is always greater than h(x), or vice versa, are incorrect.
At x = -1,
and 
So, g(x) > h(x) for x = -1............................(1)
At x = 3,
and 
Therefore, g(x) > h(x) at x = 3........................(2)
Which disproves the statement that g(x) < h(x) for x = 3.
From points (1) and (2):
For any positive x, g(x) > h(x).
For any negative x, g(x) > h(x).