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Marysya12
4 days ago
15

The gravitational force between Pluto and Charon is 3.61 × 1018 N. Pluto has a mass of 1.3 × 1022 kg, which is only slightly gre

ater than Charon’s mass of 1.6 × 1021 kg.
How far apart are Pluto and Charon?

a.2.0 × 107 m
b.2.4 × 1012 m
c.3.8 × 1014 m
d.5.8 × 1024 m
Mathematics
1 answer:
lawyer [9.2K]4 days ago
8 0
The formula for gravitational force is F = G * m1 * m2 / r². The gravitational constant is G = 6.67 * 10^(-11) m³/kgs². Thus, we find r = sqrt(G * m1 * m2 / F) = sqrt(6.67 * 10^(-11) m³/kgs² * 1.3 * 10^(22) kg * 1.6 * 10^(21) / 3.61 * 10^(18) N) = sqrt(3.84 * 10^(14)) = 1.96 * 10^(7) m, which is approximately 2 * 10^(7) m.
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Using the extended Euclidean algorithm, find the multiplicative inverse of a. 1234 mod 4321 b. 24140 mod 40902
AnnZ [9099]

(a) The multiplicative inverse of 1234 (mod 4321) is x so that 1234*x ≡ 1 (mod 4321). We can apply Euclid's algorithm:

4321 = 1234 * 3 + 619

1234 = 619 * 1 + 615

619 = 615 * 1 + 4

615 = 4 * 153 + 3

4 = 3 * 1 + 1

Now we will express 1 as a linear combination of 4321 and 1234:

1 = 4 - 3

1 = 4 - (615 - 4 * 153) = 4 * 154 - 615

1 = 619 * 154 - 155 * (1234 - 619) = 619 * 309 - 155 * 1234

1 = (4321 - 1234 * 3) * 309 - 155 * 1234 = 4321 * 309 - 1082 * 1234

This reduces to

1 ≡ -1082 * 1234 (mod 4321)

Thus, the inverse is

-1082 ≡ 3239 (mod 4321)

(b) Since both 24140 and 40902 are even, their GCD cannot equal 1, indicating no inverse exists.

8 0
1 month ago
A child designs a flag in the shape of a rhombus, as shown in the diagram below. Which expression can be used to determine the s
Zina [9171]
<span>Which formula can be applied to find the side length of the rhombus?

 The correct answer is the first choice: 10/Cos(30°)

 Explanation:

 1. The figure shows a right triangle, where the hypotenuse is denoted by "x," and this is the length you are solving for. Therefore, you have:

 Cos(</span>α)=Adjacent side/Hypotenuse
<span>
 </span>α=30°
<span> Adjacent side=(20 in)/2=10 in
 Hypotenuse=x

 2. Inputting these numbers into the equation yields:
</span>
 Cos(α)=Adjacent side/Hypotenuse
<span> Cos(30°)=10/x

 3. Hence, by isolating the hypotenuse "x," you arrive at the expression to find the side length of the rhombus, as shown below:

 x=10/Cos(30°)
</span>

7 0
4 days ago
A waterbed filled with water has the dimensions 8ft by 7 ft by .75 ft taking the density of water to be 1.00/gm cubed how many k
Svet_ta [9500]

Density can be defined as:

D = \frac{m}{V}

Where:

m is mass

V stands for volume

To isolate the mass, we derive:

m = DV

Volume can be expressed as:

V = (8) * (7) * (0.75)

V = 42ft ^ 3

We then use the following conversion:

1foot = 0.3048m

After applying the conversion, we arrive at:

V = 42 * (0.3048) ^ 3

V = 1.19m ^ 3

Additionally, we have these conversions:

1m = 100cm

1Kg = 1000g

When we apply these conversions for density, we conclude:

D = (1\frac{g}{cm^3})((\frac{100}{1})^3\frac{cm^3}{1m^3})(\frac{1}{1000}\frac{Kg}{g})=1000\frac{Kg}{m^3}

Finally, the mass of the water required is:

m = (1000) * (1.19)

m = 1190

Answer:

A total of 1190 kilograms of water is needed to fill the waterbed.

7 0
29 days ago
Consider the next 1000 98% CIs for μ that a statistical consultant will obtain for various clients. Suppose the data sets on whi
lawyer [9240]

Answer:

d) Both blocks experienced equivalent energy loss due to friction

Explanation:

As stated in the question, two tractors are pulling two identical stone blocks the same distance across similar surfacesAdditionally, block A moves at double the speed of block B when completing the race

This implies both blocks suffer from comparable friction loss

Moreover, we understand that

Energy loss from friction is E(X) = np

Thus, the friction loss should be identical for both blocks

therefore, option d is the accurate choice p = 0.98

6 0
2 days ago
It takes 45 minutes to drive to the nearest bowling alley taking city streets going
tester [8842]
21 minutes. Step-by-step explanation: Considering the following: Using CITY STREET: The duration to drive to the nearest bowling alley is 45 minutes, which is 0.75 hours. The travel speed is 30 miles per hour. Switching to FREEWAY: the travel speed here is 65 miles per hour. Assuming both routes cover the same distance, the time required on the FREEWAY will be as follows: The distance calculated using the city route results in 30 mph = distance / 0.75 hour, giving a distance of 22.5 miles. As the distance remains consistent: Time taken on the FREEWAY = distance / speed, which results in 22.5 / 65 = 0.3461538 hours. Converting to minutes = 0.3461538 × 60, which rounds to approximately 21 minutes.
7 0
11 days ago
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